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Question answer Part II # 4

Question answer Part II # 4

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question answer Part II # 4
Page RESISTORS IN PARALLEL V I R2 I2 R3 I3 1 1 1 1 V Req %D R R, R, R, eq Voltage drops are the same throughout the entire circuit. Current is not the same. PART I For the following problems, be sure to draw a diagram for each circuit and label all the components. Use a separate sheet of paper. 1. A5Q light bulb is connected to a 10 V battery. A) Draw a diagram of the circuit indicating current flow and voltage drops. B) Calculate the current through the light bulb. 2. Power is equal to the voltage times the current, P = VI. The unit of power is the Watt, W. A) Calculate the power used by the light bulb in Problem 1. B) Is this bulb very bright? C) What is the power used by the light bulb if a 20 V battery was used instead (Don't forget to recalculate the current)? 3. What is the equivalent resistance of two 10 2 resistors and one 5 resistor connected in A) series? B) What is the current in the circuit if the applied voltage is 50 V? C) Calculate the voltage drop across each resistor. D) What is the power dissipated in each resistor? 4. What is the equivalent resistance of two 10 2 resistors and one 5 2 resistor connected in A) parallel? The current is not the same throughout the circuit; however, the voltage drop across each resistor is the same as the applied voltage. B) What is the current through each resistor if the applied voltage is 50 V? C) What is the power dissipated in each resistor? D) Is your house connected in series or parallel? PART II For the following problems take screenshots, paste them into ONE document, i.e. Word, and upload them to IvyLearn. 1. For Problem 1 in PART I construct the circuit with an ammeter built into the circuit to show the current and the voltmeter to show the drop in voltage across the resistor. (There is one screenshot for this problem.) 2. For Problem 2 in PART I use the circuit that you created for Problem 1 and change the voltage to 20 V. The ammeter should show the new value of current. (There is one screenshot for this problem.) 3. For Problem 3 in PART I construct the series circuit with an ammeter built into the circuit. Place the ammeter after the battery. Then construct the equivalent circuit with a built-in ammeter to show that the current is the same. (There are two screenshots for this problem.) 4. For Problem 4 in PART II construct the parallel circuit as shown in the Circuit Construction Kit Tutorial. Then construct the equivalent circuit with a built-in ammeter to show that the current coming from the battery is the same. (There are two screenshots for this problem.) WWW
Transcribed Image Text:Page RESISTORS IN PARALLEL V I R2 I2 R3 I3 1 1 1 1 V Req %D R R, R, R, eq Voltage drops are the same throughout the entire circuit. Current is not the same. PART I For the following problems, be sure to draw a diagram for each circuit and label all the components. Use a separate sheet of paper. 1. A5Q light bulb is connected to a 10 V battery. A) Draw a diagram of the circuit indicating current flow and voltage drops. B) Calculate the current through the light bulb. 2. Power is equal to the voltage times the current, P = VI. The unit of power is the Watt, W. A) Calculate the power used by the light bulb in Problem 1. B) Is this bulb very bright? C) What is the power used by the light bulb if a 20 V battery was used instead (Don't forget to recalculate the current)? 3. What is the equivalent resistance of two 10 2 resistors and one 5 resistor connected in A) series? B) What is the current in the circuit if the applied voltage is 50 V? C) Calculate the voltage drop across each resistor. D) What is the power dissipated in each resistor? 4. What is the equivalent resistance of two 10 2 resistors and one 5 2 resistor connected in A) parallel? The current is not the same throughout the circuit; however, the voltage drop across each resistor is the same as the applied voltage. B) What is the current through each resistor if the applied voltage is 50 V? C) What is the power dissipated in each resistor? D) Is your house connected in series or parallel? PART II For the following problems take screenshots, paste them into ONE document, i.e. Word, and upload them to IvyLearn. 1. For Problem 1 in PART I construct the circuit with an ammeter built into the circuit to show the current and the voltmeter to show the drop in voltage across the resistor. (There is one screenshot for this problem.) 2. For Problem 2 in PART I use the circuit that you created for Problem 1 and change the voltage to 20 V. The ammeter should show the new value of current. (There is one screenshot for this problem.) 3. For Problem 3 in PART I construct the series circuit with an ammeter built into the circuit. Place the ammeter after the battery. Then construct the equivalent circuit with a built-in ammeter to show that the current is the same. (There are two screenshots for this problem.) 4. For Problem 4 in PART II construct the parallel circuit as shown in the Circuit Construction Kit Tutorial. Then construct the equivalent circuit with a built-in ammeter to show that the current coming from the battery is the same. (There are two screenshots for this problem.) WWW
Background: James Clerk Maxwell (1860's) can be considered the father of electromagnetics, just as Newton is considered the father of mechanics. Einstein adopted many ideas from Maxwell while formulating his theories. Maxwell wrote four governing equations in electromagnetic theory. These equations have a broad and diverse application in several phenomenon involving light, electricity, and magnetism (electromagnetism!). Objective: Examine two basic circuits: series and parallel. Examine two basic circuit components: voltage source and resistor. Learn how to determine equivalent resistance to solve circuit problems using Ohm's Law. Calculate the electrical power, P = VI. Procedure: The simplest circuit is a voltage source (i.e. battery) and resistor. The voltage 'pushes' the current through the circuit. The resistor turns some of the current into heat (or light), and thus, the voltage across a resistor drops. This is called Ohm's Law: V = RI. R V Circuits can contain several resistors. In circuit analysis, it is convenient to reduce all resistors to one equivalent resistance. Two possible arrangements are called series, and parallel. The diagrams below show these arrangements, the corresponding equivalent resistances, and the main conclusions of each arrangement. RESISTORS IN EQUIVALENT RESISTANCE R1 SERIES V R2 AAA Reg = R, + R, + R, V Req R3 Current is the same throughout the entire circuit. Voltage drops are not the same.
Transcribed Image Text:Background: James Clerk Maxwell (1860's) can be considered the father of electromagnetics, just as Newton is considered the father of mechanics. Einstein adopted many ideas from Maxwell while formulating his theories. Maxwell wrote four governing equations in electromagnetic theory. These equations have a broad and diverse application in several phenomenon involving light, electricity, and magnetism (electromagnetism!). Objective: Examine two basic circuits: series and parallel. Examine two basic circuit components: voltage source and resistor. Learn how to determine equivalent resistance to solve circuit problems using Ohm's Law. Calculate the electrical power, P = VI. Procedure: The simplest circuit is a voltage source (i.e. battery) and resistor. The voltage 'pushes' the current through the circuit. The resistor turns some of the current into heat (or light), and thus, the voltage across a resistor drops. This is called Ohm's Law: V = RI. R V Circuits can contain several resistors. In circuit analysis, it is convenient to reduce all resistors to one equivalent resistance. Two possible arrangements are called series, and parallel. The diagrams below show these arrangements, the corresponding equivalent resistances, and the main conclusions of each arrangement. RESISTORS IN EQUIVALENT RESISTANCE R1 SERIES V R2 AAA Reg = R, + R, + R, V Req R3 Current is the same throughout the entire circuit. Voltage drops are not the same.
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