Question a) The 10-kg block has a speed of 4 m/s when the force of F = (8t²) N is applied (Figure Q2(a)). Determine the velocity of the block at t = 10 s. The coefficient of kinetic friction at the surface is μk = 0.2. F = (81²) N v = 4 m/s
Question a) The 10-kg block has a speed of 4 m/s when the force of F = (8t²) N is applied (Figure Q2(a)). Determine the velocity of the block at t = 10 s. The coefficient of kinetic friction at the surface is μk = 0.2. F = (81²) N v = 4 m/s
Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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a) The 10-kg block has a speed of 4 m/s when the force of F = (8t²) N is applied (Figure Q2(a)).
Determine the velocity of the block at t = 10 s. The coefficient of kinetic friction at the surface is
μk = 0.2.
F = (81²) N
v = 4 m/s
Figure Q2(a)
b) The force of F = 50 N is applied to the cord when s = 2 m as shown in Figure Q2(b). If the 6-kg
collar is originally at rest, determine its velocity at s = 0. Neglect friction.
1.5 m
F
Figure Q2(b)
A"
Transcribed Image Text:Question
a) The 10-kg block has a speed of 4 m/s when the force of F = (8t²) N is applied (Figure Q2(a)).
Determine the velocity of the block at t = 10 s. The coefficient of kinetic friction at the surface is
μk = 0.2.
F = (81²) N
v = 4 m/s
Figure Q2(a)
b) The force of F = 50 N is applied to the cord when s = 2 m as shown in Figure Q2(b). If the 6-kg
collar is originally at rest, determine its velocity at s = 0. Neglect friction.
1.5 m
F
Figure Q2(b)
A
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