25. Need C, C++, Java, Python, or Perl code for the below question. Important: Do not copy codes from prepinsta.com. **Question:** A chocolate factory is packing chocolates into packets. The chocolate packets here represent an array of N number of integer values. The task is to find the empty packets (0) of chocolate and push them to the end of the conveyor belt (array).**Example 1:**N = 7 and arr = [4, 5, 0, 1, 9, 0, 5, 0].There are 3 empty packets in the given set. These 3 empty packets represented as 0 should be pushed towards the end of the array.**Input:**7 – Value of N[4, 5, 0, 1, 9, 0, 5, 0] – Elements from arr[0] to arr[N-1], with each input element separated by a newline.**Output:**4 5 1 9 5 0 0 0**Example 2:****Input:**6 – Value of N[6, 0, 1, 8, 0, 2] – Elements from arr[0] to arr[N-1], with each input element separated by a newline.**Output:**6 1 8 2 0 0

Solution: Solution in java languageCode: class PushZero { static void emptyPacketsToEnd(int arr[], int n) { // Count of non-zero elements int count = 0; // Traverse the array. If element encountered is non-zero, then replace the element at index 'count' with this element for (int i = 0; i < n; i++) if (arr[i] != 0){ // here count is incremented arr[count++] = arr[i]; } // Now all non-zero elements have been shifted to front and 'count' is set as index of first 0. // Make all elements 0 from count to end. while (count < n) arr[count++] = 0; } // main function public static void main (String[] args) { int arr1[] = {4, 5, 0, 9, 0, 5, 0}; int arr2[] = {6, 0, 1, 8, 0, 2}; emptyPacketsToEnd(arr1, 7); emptyPacketsToEnd(arr2, 6); System.out.println("Array after pushing empty packets to end: "); for (int i=0; i<7; i++){ System.out.print(arr1[i]+" "); } System.out.println(); //changing the line System.out.println("Array after pushing empty packets to end: "); for (int i=0; i<6; i++){ System.out.print(arr2[i]+" "); } System.out.println(); //changing the line }}Code snip: Output: