Question 9 of 10 > O Attempt 8 Calculate the higher derivative. < E Feedback (Use symbolic notation and fractions where needed.) Use the Product Rule to find the first and the second derivatives. (f · g)' = f' ·g + f. 8' d? -16 cos? (t) = dt2 |- 16 sin? (t) Recall that sin(x) = cos(x) and cos(x) = - sin(x). Incorrect dx
Question 9 of 10 > O Attempt 8 Calculate the higher derivative. < E Feedback (Use symbolic notation and fractions where needed.) Use the Product Rule to find the first and the second derivatives. (f · g)' = f' ·g + f. 8' d? -16 cos? (t) = dt2 |- 16 sin? (t) Recall that sin(x) = cos(x) and cos(x) = - sin(x). Incorrect dx
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Can I get some help with this please, thank you!
![**Calculate the Higher Derivative**
*Instruction: Use symbolic notation and fractions where needed.*
Problem:
\[ \frac{d^2}{dt^2} 16 \cos^2(t) = \]
Solution:
The attempted solution is:
\[ -16 \sin^2(t) \]
*The answer is marked as incorrect.*
**Feedback**
Use the Product Rule to find the first and the second derivatives.
The Product Rule is given by:
\[ (f \cdot g)' = f' \cdot g + f \cdot g' \]
Recall that:
\[ \frac{d}{dx} \sin(x) = \cos(x) \]
and
\[ \frac{d}{dx} \cos(x) = -\sin(x) \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F780752d8-13ba-4fd6-830b-ece462d6e91e%2Ff32ac18c-9574-4ed0-9980-39eb698e48d6%2Fwgjoy9g_processed.png&w=3840&q=75)
Transcribed Image Text:**Calculate the Higher Derivative**
*Instruction: Use symbolic notation and fractions where needed.*
Problem:
\[ \frac{d^2}{dt^2} 16 \cos^2(t) = \]
Solution:
The attempted solution is:
\[ -16 \sin^2(t) \]
*The answer is marked as incorrect.*
**Feedback**
Use the Product Rule to find the first and the second derivatives.
The Product Rule is given by:
\[ (f \cdot g)' = f' \cdot g + f \cdot g' \]
Recall that:
\[ \frac{d}{dx} \sin(x) = \cos(x) \]
and
\[ \frac{d}{dx} \cos(x) = -\sin(x) \]
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