Question 9 Consider the following function: f(x) = x³ – 3x² + 2x + 10 Your friend is using a numerical method to approximate 1and his approximation is f(1) =9.12. The true absolute percent relative error is [1] % and the absolute true error is [2]. Next, suppose that your friend achieves a better approximation f(1) = 9.9. The approximate absolute percent relative error is [3] % and the absolute approximate error is [4] Note: round up to 2 decimal places.
Question 9 Consider the following function: f(x) = x³ – 3x² + 2x + 10 Your friend is using a numerical method to approximate 1and his approximation is f(1) =9.12. The true absolute percent relative error is [1] % and the absolute true error is [2]. Next, suppose that your friend achieves a better approximation f(1) = 9.9. The approximate absolute percent relative error is [3] % and the absolute approximate error is [4] Note: round up to 2 decimal places.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Question 9
Consider the following function
f(x) = x³ – 3x² + 2x + 10
Your friend is using a numerical method to approximate 1and his approximation is f(1) = 9.12. The true absolute percent relative error is [1] % and the absolute true error is [2].
Next, suppose that your friend achieves a better approximation f(1) = 9.9.
The approximate absolute percent relative error is [3] %
and the absolute approximate error is [4]
Note: round up to 2 decimal places](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd84795ed-cd84-4746-b8f0-c43d686390e0%2Fbe57ebc9-e1ae-4699-b445-a3bc6492f700%2Fgedn8d9_processed.png&w=3840&q=75)
Transcribed Image Text:Question 9
Consider the following function
f(x) = x³ – 3x² + 2x + 10
Your friend is using a numerical method to approximate 1and his approximation is f(1) = 9.12. The true absolute percent relative error is [1] % and the absolute true error is [2].
Next, suppose that your friend achieves a better approximation f(1) = 9.9.
The approximate absolute percent relative error is [3] %
and the absolute approximate error is [4]
Note: round up to 2 decimal places
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