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- List all groups of order up to 12, Then *Note that the groups of order up to 12 must contain cyclic group, symmetric group, alternating group and dihedral group, additional groups are also preferredThe multiplicative group of positive rational number is cyclic If its true give detailed proof if its not ture give exampleDetermine all subgroups of R* (nonzero reals under multiplication)of index 2.
- 3Are there any other subgroups of = order 3 & 2 ? For his vere'll consider all subsets of 3 and 2 elements of $3 and use equations of fiz and gf² = fg to check if they are subgroups 5-{e, f, f²g, fg, f²g] } All Subsets of 3 elements { e. f₁ f²} = = {e₁ he₁ f₁ g y = Not a Subgp. Since £g¢{ } 2 17 {e, f, f'g]=" { e, f ²₁ gb = {e, f²₁ fg} = 11 {e, 5², 3²g} = 11 11 " "1 11 11 " since f.f²g = fg-=9& { } Since 1²g & {y • Since f²fg. f²f g - f³ g - g 4 2 3 Since f²f²g = f g = fg &{} L> 71 Ee, g, fg} = not a subgp. since gffg)=ggf}=1² #23 Ee, g, fg}= Since g(8²) = g(gf) = f 483 E g, fg, fg}.. Since gf ggf) f €23 So the only subgroups of order. 3 are , 11 2 (1A_4 in S_4 Find solutions to pic attached
- Plz don't use chat gptA group G has come to talk to you. You find out that G has 100 = 22 x 52 elements and that G has exactly one subgroup of order 10 whose name is Н. (a) Remind yourself, by rereading Example 10.7, why H must be a nor- mal subgroup of G. (b) Let PE Syl;(G). What can you say about |P|, |H^P|, and |(H, P)|? Prove your assertions. (c) The group G is guaranteed to have subgroups of which sizes?When do you use a t-test for independent groups and what do the numerator and deniminator in the formula represent?