Question 8- Show work for 1-2. Students of a small university who eat lunch on campus spend an average of $6.25 a day at their cafeteria. The standard deviation of the expenditure is $1.25. The data is normally distributed. 1. What is the z score of Frank who spent $6.00? 2. What probability corresponds with Frank's z score? 3. Why was Frank's z score negative? Why was his probability positive? Doria spent $3.15 on her lunch on Friday. Explain to her, in terms of standard deviation, why this is not a typical expenditure at this campus.

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Question 8- Show work for 1-2.
Students of a small university who eat lunch on campus spend an average of $6.25 a
day at their cafeteria. The standard deviation of the expenditure is $1.25. The data is
normally distributed.
1. What is the z score of Frank who spent $6.00?
2. What probability corresponds with Frank's z score?
3. Why was Frank's z score negative? Why was his probability positive?
4. Doria spent $3.15 on her lunch on Friday. Explain to her, in terms of standard deviation, why this is not a
typical expenditure at this campus.
Transcribed Image Text:Question 8- Show work for 1-2. Students of a small university who eat lunch on campus spend an average of $6.25 a day at their cafeteria. The standard deviation of the expenditure is $1.25. The data is normally distributed. 1. What is the z score of Frank who spent $6.00? 2. What probability corresponds with Frank's z score? 3. Why was Frank's z score negative? Why was his probability positive? 4. Doria spent $3.15 on her lunch on Friday. Explain to her, in terms of standard deviation, why this is not a typical expenditure at this campus.
Expert Solution
Step 1

Given:

μ=6.25,σ=1.25

 

Step 2

1. z-score:

z=x-μσ=6-6.251.25=-0.2

 

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