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QUESTION 8 In calculating the current in an electric circuit with an inductance L. a resistance R, and a capacitance C; it is necessary to solve the following equation: Lm? + Rm + 1/c = 0 %3D Solve for m, in terms of L, Rand C. lell C Fig. 7.6 Copyright © 2015 Pearson Canada Inc. 2L +R t R2 - C m = 2L 4L R2 -2R + m = 7. 4L R2 C -R + m = 2L R2 40 -R t m = 3L |-19|

QUESTION 8 In calculating the current in an electric circuit with an inductance L. a resistance R, and a capacitance C; it is necessary to solve the following equation: Lm? + Rm + 1/c = 0 %3D Solve for m, in terms of L, Rand C. lell C Fig. 7.6 Copyright © 2015 Pearson Canada Inc. 2L +R t R2 - C m = 2L 4L R2 -2R + m = 7. 4L R2 C -R + m = 2L R2 40 -R t m = 3L |-19|

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QUESTION 8 In calculating the current in an electric circuit with an inductance L. a resistance R, and a capacitance C; it is necessary to solve the following equation: Lm? + Rm + 1/c = 0 %3D Solve for m, in terms of L, Rand C. ell Fig. 7.6 Copyright © 2015 Pearson Canada Inc. 2L +R t R2 - C m = 2L 4L R2 -2R + m 3= 4L R2 C m = 2L -R + R2 m = 3L |-19|
Transcribed Image Text:QUESTION 8 In calculating the current in an electric circuit with an inductance L. a resistance R, and a capacitance C; it is necessary to solve the following equation: Lm? + Rm + 1/c = 0 %3D Solve for m, in terms of L, Rand C. ell Fig. 7.6 Copyright © 2015 Pearson Canada Inc. 2L +R t R2 - C m = 2L 4L R2 -2R + m 3= 4L R2 C m = 2L -R + R2 m = 3L |-19|
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