O 0.4354QUESTION 84.Body Temperature. The body temperatures of adults are normally distributed with a mean of 98.6 degrees Fahrenheit and a standard deviationof 0.81 degrees Fahrenheit. What temperature represents the 95 percentile? (4 points) (CHOOSE ONE ANSWER) HINT: 95th percentilemeans that 95% of all values are BELOW this temperature and 5% of all values are ABOVE this temperature.O 97.27°FO100 19 F99.93 F99.64 FQUESTION 94 FHuman Pregnancies. The lengths of pregnancies of humans are normally distributed with a mean of 268 davs and a standard deviation of 15days. Find the probability of a pregnancy lasting less than 250 days. (CHOOSE ONE ANSWER) (4 points).Save All AnswersClick Save and Submit to save and subrmit. Clhick Save All Answers fo saue all answers.off and orarch

Given that mean = 98.6 s.d = 0.81 95th percentile = ?

Answered: QUESTION 8 Body Temperature. The body…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Heights for group of people normally distributed with mean = 63 inches and standard deviation = 2.6 inches. Find the height, h such that about 10% of people in the group are shorter than that height. (Round the answer to the nearest tenth.)h = in.What is the percentile, p ranking for that height? p = % You may need to use the appropriate table in the Appendix of Tables to answer this question.
The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean u = $1.481 and standard deviation a = $0.971. E Click the icon to view the frequency distribution for the tax rates. The population mean is S. (Round to three decimal places as needed.) Frequency distribution cigarette tax rates - X The population standard deviation is S (Round to three decimal places as needed.) Tax Rate 0.00-0.49 0.50-0.99 1.00-1.49 1.50-1.99 2.00-2.49 2.50-2. 99 3.00-3.49 3.50-399 4.00 4.49 Frequency O Compare these results to the values found using the actual data. 14 O A. The grouped values are both slightly larger. O B. The grouped values are both slightly' smaller. O C. The grouped mean is slightly larger, while the grouped standard deviation is slightly smaller. 17 O D. The grouped mean is slightly smaller, while the…
The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean μ = $1.638 and standard deviation o = $1.052. Click the icon to view the frequency distribution for the tax rates. The population mean is $ (Round to three decimal places as needed.) book Get more help. C *** Frequency distribution of cigarette tax rates G Search or type URL Tax Rate 0.00-0.49 0.50-0.99 1.00-1.49 1.50-1.99 2.00-2.49 2.50-2.99 3.00-3.49 3.50-3.99 4.00-4.49 Print Frequency O 7 12 6 6 6 6 3 3 1 Done - X Clear all Check answer
Kirsten's quiz grade in her biology class is 63.5. If her class mean is 74 and the standard deviation is 7, what is Kirsten's Z-sore? -0.5 7 None of these
Please answer within 30min thanks.
Heights for group of people normally distributed with mean = 65 inches and standard deviation = 2.5 inches. Find the height, h such that about 20% of people in the group are shorter than that height. (Round the answer to the nearest tenth.) h = in. What is the percentile, p ranking for that height?p = %
Use the table to answer the question. Note: Round z-scores to the nearest hundredth and then find the required A values using the table.A biologist found the wingspans of a group of monary butterflies to be normally distributed with a mean of 52.8 mm and a standard deviation of 2.5 mm. What percent of the butterflies had the following wingspans? (Round your answers to one decimal place.) (a) less than 48.7 mm %(b) between 50 and 55 mm %
I was wondering if these answers are correct. Explain. A study by Quadrant Information Services commissioned by Insure.com calculated auto insurance rates for each of the 50 states; and as a result, the average annual rate for the United States was $1,317. Suppose annual rates of auto insurance in the United States are normally distributed with a standard deviation of $324. According to MoneyGeek, a state minimum auto insurance policy in Florida costs an average of $1123 per year and the average cost of full coverage car insurance in Florida is $2208. What percentage of policies cost less than the Florida state minimum policy of $1123? z = (x - mu) / sigma z = (1123-1317)/324 z= -0.59876543 P-value from Z-Table: P(x<1123) = 0.27466 The answer is less than I expected. After using a z-table to determine the score it results in 27% of policies that are less than the minimum policy of 1123. What percentage of auto insurance rates would be less than $1,200? z = (x - mu) / sigma…
Use the table to answer the question. Note: Round z-scores to the nearest hundredth and then find the required A values using the table.The cholesterol levels of a group of young women at a university are normally distributed, with a mean of 181 and a standard deviation of 38. What percent of the young women have the following cholesterol levels? (Round your answers to one decimal place.) (a) greater than 223 %(b) between 186 and 222 %
A Moving to another question will save this response. Question 5 The national scores on an exam were normal distributed with a mean of 428 and a standard deviation of 113. Approximately what percent of those taking this test had scores between 315 and 541? A Moving to another question will save this response. Session 10 GN.docx MacBook Pro
Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to P34, the 84th percentile. This is the temperature reading separating the bottom 84% from the top 16%. Click to view page 1 of the table. Click to view page 2 of the table. Which graph represents P ? Choose the correct graph below. 84 A. В. OC. D. Ay X The temperature for P84 is approximately (Round to two decimal places as needed.)
A normal population has mean u = 50 and standard deviation o = 5. What is the 80th percentile of the population? Use the TI-84 Plus calculator. Round the answer to at least one decimal place.

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