Question 7 < > CNNBC recently reported that the mean annual cost of auto insurance is 985 dollars. Assume the standard deviation is 181 dollars. You will use a simple random sample of 142 auto insurance policies. Find the probability that a single randomly selected policy has a mean value between 985 and 986.5 dollars. P(985 < X < 986.5) = Find the probability that a random sample of size n = 142 has a mean value between 985 and 986.5 dollars. P(985 M 986.5) = Enter your answers as numbers accurate to 4 decimal places. Question Help: Video Submit Question
Question 7 < > CNNBC recently reported that the mean annual cost of auto insurance is 985 dollars. Assume the standard deviation is 181 dollars. You will use a simple random sample of 142 auto insurance policies. Find the probability that a single randomly selected policy has a mean value between 985 and 986.5 dollars. P(985 < X < 986.5) = Find the probability that a random sample of size n = 142 has a mean value between 985 and 986.5 dollars. P(985 M 986.5) = Enter your answers as numbers accurate to 4 decimal places. Question Help: Video Submit Question
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Transcribed Image Text:### Question 7
CNNBC recently reported that the mean annual cost of auto insurance is 985 dollars. Assume the standard deviation is 181 dollars. You will use a simple random sample of 142 auto insurance policies.
1. **Find the probability that a single randomly selected policy has a mean value between 985 and 986.5 dollars.**
\( P(985 < X < 986.5) = \)
2. **Find the probability that a random sample of size \( n = 142 \) has a mean value between 985 and 986.5 dollars.**
\( P(985 < M < 986.5) = \)
Enter your answers as numbers accurate to 4 decimal places.
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