QUESTION 7 6.29c: Select the most relevant answer Hint: See L-15 pdf and lecture, page 8-11 (Exercise 6.11) O! Since n-1=29<30, CLT is no help. We need to ASSUME that the sample mean (of the differences) is normally distributed. It is clear from the problem description that the twin pairs are randomly selected. O" Since n=30 2 30, CLT states that the sample mean (of the differences) is normally distributed. It is clear from the problem description that the twin pairs are randomly selected. Since n-1=29<30, CLT is no help. We need to ASSUME that the sample mean (of the differences) is normally distributed. It is unclear from the problem description that the twin pairs are randomly selected. Ow Since n=30 > 30, CLT states that the sample mean (of the differences) is normally distributed. It is unclear from the problem description that the twin pairs are randomly selected.

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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QUESTION 7
6.29c: Select the most relevant answer
Hint: See L-15 pdf and lecture, page 8-11 (Exercise 6.11)
Ol Since n-1=29<30, CLT is no help. We need to ASSUME that the
sample mean (of the differences) is normally distributed. It is clear
from the problem description that the twin pairs are randomly
selected.
O" Since n=30 2 30, CLT states that the sample mean (of the
differences) is normally distributed. It is clear from the problem
description that the twin pairs are randomly selected.
Since n-1=29<30, CLT is no help. We need to ASSUME that the
sample mean (of the differences) is normally distributed. It is
unclear from the problem description that the twin pairs are
randomly selected.
O Since n=30 2 30, CLT states that the sample mean (of the
differences) is normally distributed. It is unclear from the problem
description that the twin pairs are randomly selected.
Transcribed Image Text:QUESTION 7 6.29c: Select the most relevant answer Hint: See L-15 pdf and lecture, page 8-11 (Exercise 6.11) Ol Since n-1=29<30, CLT is no help. We need to ASSUME that the sample mean (of the differences) is normally distributed. It is clear from the problem description that the twin pairs are randomly selected. O" Since n=30 2 30, CLT states that the sample mean (of the differences) is normally distributed. It is clear from the problem description that the twin pairs are randomly selected. Since n-1=29<30, CLT is no help. We need to ASSUME that the sample mean (of the differences) is normally distributed. It is unclear from the problem description that the twin pairs are randomly selected. O Since n=30 2 30, CLT states that the sample mean (of the differences) is normally distributed. It is unclear from the problem description that the twin pairs are randomly selected.
6.29 A study was designed to measure the effect of home environment on academic achieve-
ment of 12-year-old students. Because genetic differences may also contribute to academic
achievement, the researcher wanted to control for this factor. Thirty sets of identical twins were
identified who had been adopted prior to their first birthday, with one twin placed in a home in
which academics were emphasized (Academic) and the other twin placed in a home in which
academies were not emphasized (Nonacademic). The final grades (based on 100 points) for the 60
students are given here.
Set of
Set of
Twins
Academic
Nonacademic
Twins
Academic
Nonacademic
1
78
71
16
90
88
2
75
70
17
89
80
3
68
66
18
73
65
92
85
19
61
60
55
60
20
76
74
74
72
21
81
76
7
65
57
22
89
78
8
80
75
82
78
98
92
70
62
10
68
73
11
67
63
74
73
12
55
52
85
75
13
49
48
28
97
88
14
95
94
15
75
70
30
78
75
a. Is there a difference in the mean final grades between the students in an academi-
cally oriented home environment and those in a nonacademically oriented home
environment. Use a- 05.
b. Estimate the size of the difference in the mean final grades of the students in
academic and nonacademic home environments using a 95% confidence interval.
c. Do the conditions for using the procedures appear to be satisfied for these data?
d. Does it appear that using twins in this study to control for variation in final scores
was effective as compared to taking a random sample of 30 students in both types
of home environments? Justify your answer.
Act
Gote
Transcribed Image Text:6.29 A study was designed to measure the effect of home environment on academic achieve- ment of 12-year-old students. Because genetic differences may also contribute to academic achievement, the researcher wanted to control for this factor. Thirty sets of identical twins were identified who had been adopted prior to their first birthday, with one twin placed in a home in which academics were emphasized (Academic) and the other twin placed in a home in which academies were not emphasized (Nonacademic). The final grades (based on 100 points) for the 60 students are given here. Set of Set of Twins Academic Nonacademic Twins Academic Nonacademic 1 78 71 16 90 88 2 75 70 17 89 80 3 68 66 18 73 65 92 85 19 61 60 55 60 20 76 74 74 72 21 81 76 7 65 57 22 89 78 8 80 75 82 78 98 92 70 62 10 68 73 11 67 63 74 73 12 55 52 85 75 13 49 48 28 97 88 14 95 94 15 75 70 30 78 75 a. Is there a difference in the mean final grades between the students in an academi- cally oriented home environment and those in a nonacademically oriented home environment. Use a- 05. b. Estimate the size of the difference in the mean final grades of the students in academic and nonacademic home environments using a 95% confidence interval. c. Do the conditions for using the procedures appear to be satisfied for these data? d. Does it appear that using twins in this study to control for variation in final scores was effective as compared to taking a random sample of 30 students in both types of home environments? Justify your answer. Act Gote
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