f'(x) = -6x²-6x (0) − 2(0)² + 2x + (0) - f'(x) = lim −2x³-6x²h−6xh²=2h³+x²+2xh+h²+1+2xª³¬x²−1 h→0 h ❤ h(-6x²-6xh-2h2+2x+h) f'(x) = lim h→0 ☐ [-2x³-6x²h-6xh²-2h³+x²+2xh+h²+1]-[−2x³+x²+1] f'(x) = lim h→0 f'(x) = lim -62³h-62h2_2h³+2xh+h² h h→0 Question 7 2d. Order the steps, using first principles, to solve for the derivative of the equation f(x) = -2x3 + x2 +1. f'(x) = lim f(x+h)-f(x) h h→0 f'(x) = lim h→0 =2(x+h)³+(x+h)²+1]-[−2x³+x²+1] h f'(x) = -6x²+2x
f'(x) = -6x²-6x (0) − 2(0)² + 2x + (0) - f'(x) = lim −2x³-6x²h−6xh²=2h³+x²+2xh+h²+1+2xª³¬x²−1 h→0 h ❤ h(-6x²-6xh-2h2+2x+h) f'(x) = lim h→0 ☐ [-2x³-6x²h-6xh²-2h³+x²+2xh+h²+1]-[−2x³+x²+1] f'(x) = lim h→0 f'(x) = lim -62³h-62h2_2h³+2xh+h² h h→0 Question 7 2d. Order the steps, using first principles, to solve for the derivative of the equation f(x) = -2x3 + x2 +1. f'(x) = lim f(x+h)-f(x) h h→0 f'(x) = lim h→0 =2(x+h)³+(x+h)²+1]-[−2x³+x²+1] h f'(x) = -6x²+2x
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![f'(x) = -6x²-6x (0) − 2(0)² + 2x + (0)
-
f'(x) = lim −2x³-6x²h−6xh²=2h³+x²+2xh+h²+1+2xª³¬x²−1
h→0
h
❤
h(-6x²-6xh-2h2+2x+h)
f'(x) = lim
h→0
☐
[-2x³-6x²h-6xh²-2h³+x²+2xh+h²+1]-[−2x³+x²+1]
f'(x) = lim
h→0
f'(x) = lim -62³h-62h2_2h³+2xh+h²
h
h→0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd82885f1-b115-440e-b2db-f303a4907f8c%2F862f83c0-3ac6-499e-b8c7-3db8a9dbc177%2Fh3nmuia_processed.jpeg&w=3840&q=75)
Transcribed Image Text:f'(x) = -6x²-6x (0) − 2(0)² + 2x + (0)
-
f'(x) = lim −2x³-6x²h−6xh²=2h³+x²+2xh+h²+1+2xª³¬x²−1
h→0
h
❤
h(-6x²-6xh-2h2+2x+h)
f'(x) = lim
h→0
☐
[-2x³-6x²h-6xh²-2h³+x²+2xh+h²+1]-[−2x³+x²+1]
f'(x) = lim
h→0
f'(x) = lim -62³h-62h2_2h³+2xh+h²
h
h→0
![Question 7
2d. Order the steps, using first principles, to solve for the derivative of the equation
f(x) = -2x3 + x2 +1.
f'(x) = lim
f(x+h)-f(x)
h
h→0
f'(x) = lim
h→0
=2(x+h)³+(x+h)²+1]-[−2x³+x²+1]
h
f'(x) = -6x²+2x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd82885f1-b115-440e-b2db-f303a4907f8c%2F862f83c0-3ac6-499e-b8c7-3db8a9dbc177%2Fzzqkif_processed.png&w=3840&q=75)
Transcribed Image Text:Question 7
2d. Order the steps, using first principles, to solve for the derivative of the equation
f(x) = -2x3 + x2 +1.
f'(x) = lim
f(x+h)-f(x)
h
h→0
f'(x) = lim
h→0
=2(x+h)³+(x+h)²+1]-[−2x³+x²+1]
h
f'(x) = -6x²+2x
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