Question 6 When 3.50g of Bals) is added to 100.0g of water in a coffee cup calorimeter, the reaction shown below occurs, and the temperature of the resulting solution rises from 22.00°C to 47.40°C. If the specific heat of the solution is 4,184 J/g °C, calculate AH for the reaction. Bals) is the limiting reactant, and it's molar mass-137.33 g/mol Ba(s) + 2H₂O)→ Ba(OH)2(aq) + H₂(g) Equations: 1 cal-4.184 Joules 1 Latm 101.325 Joules. AE-q+w w pAV 9-mcAT (at constant pressure / coffee cup calorimetry) AE-ATxe (at constant volume/ bomb calorimetry) All-EnAH, AH +431 kJ/mol O-431 kJ/mol O 314 kJ/mol O-11.0 kl/mol O +3.14 kJ/mol CHOO-4.184 J/g °C

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Question 6
When 3.50g of Bals) is added to 100.0g of water in a coffee cup calorimeter, the reaction shown below occurs, and the temperature of the resulting solution rises from
22.00°C to 47.40°C. If the specific heat of the solution is 4.184 J/g °C, calculate AH for the reaction. Ba(s) is the limiting reactant, and it's molar mass= 137.33 g/mol
Ba(s) + 2H₂O(1)→ Ba(OH)₂(aq) + H₂(g)
Equations:
1 cal-4.184 Joules
AE-q+w
w=pAV
9-mcAT (at constant pressure / coffee cup calorimetry)
AE AT xc (at constant volume / bomb calorimetry)
AHEnAH, EnAH,
+431 kJ/mol
O-431 kJ/mol
O314 kJ/mol
O-11.0 kl/mol
O +3.14 kJ/mol
1 Latm 101.325 Joules
CH20-4.184 J/g °C.
Transcribed Image Text:Question 6 When 3.50g of Bals) is added to 100.0g of water in a coffee cup calorimeter, the reaction shown below occurs, and the temperature of the resulting solution rises from 22.00°C to 47.40°C. If the specific heat of the solution is 4.184 J/g °C, calculate AH for the reaction. Ba(s) is the limiting reactant, and it's molar mass= 137.33 g/mol Ba(s) + 2H₂O(1)→ Ba(OH)₂(aq) + H₂(g) Equations: 1 cal-4.184 Joules AE-q+w w=pAV 9-mcAT (at constant pressure / coffee cup calorimetry) AE AT xc (at constant volume / bomb calorimetry) AHEnAH, EnAH, +431 kJ/mol O-431 kJ/mol O314 kJ/mol O-11.0 kl/mol O +3.14 kJ/mol 1 Latm 101.325 Joules CH20-4.184 J/g °C.
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