Question 6 When 1.50 L of 0.225 M NaOH is mixed with 2.00 L of 0.250 M FeCl, and the following reaction occurs: 3 NaOH(aq) + FeCl3(aq) → 3 NaCl(aq) + Fe(OH), (s) What is the theoretical mass of the precipitate that will be produced? g Fe(OH)3
Question 6 When 1.50 L of 0.225 M NaOH is mixed with 2.00 L of 0.250 M FeCl, and the following reaction occurs: 3 NaOH(aq) + FeCl3(aq) → 3 NaCl(aq) + Fe(OH), (s) What is the theoretical mass of the precipitate that will be produced? g Fe(OH)3
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Question 6
When 1.50 L of 0.225 M NaOH is mixed with 2.00 L of 0.250 M FeCl, and the following
reaction occurs:
3
3 NaOH (aq) + FeCl3(aq) → 3 NaCl(aq) + Fe(OH), (s)
What is the theoretical mass of the precipitate that will be produced?
g Fe(OH)₂ 3
Question 7
IT.
Expert Solution

Step 1
Given,
3NaOH(aq) + FeCl3(aq) → 3NaCl(aq) + Fe(OH)3(s)
For NaOH solution:
Concentration of NaOH solution = 0.225 M = 0.225 mol/L
Volume of NaOH solution = 1.50 L
For FeCl3 solution:
Concentration of FeCl3 solution = 0.250 M = 0.250 mol/L
Volume of FeCl3 solution = 2.00 L
Theoretical mass of Fe(OH)3 produced = ?
Note:
molar mass of Fe(OH)3 = 106.87 g/mol
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