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Question 6 The number of credit cards in the wallet of a randomly selected person varies from 0 to 6. The probability distribution of the number of credit cards, X, is as follows: 0 1 2 3 0.33 Xi P(X = x₁) 0.03 ■ X=5 P(X=4)=0.2 P(X=2) |X=5 P(X=4)=0.2 P(X=2) 0.11 X=5 P(X=4)=0.2 P(X=2) 1. Use the random variable notation to express symbolically each of the following: An event in which the number of credit cards is exactly 5. 0.17 4 0.2 b. P(0 ≤ x ≤ 1) = c. P(X > 1) 5 0.15 The probability that the number of credit cards is exactly 2. 2. Use the above probability distribution table to find the following: a. P(3 < X <5) 6 The probability that the number of credit cards is exactly 4 is equal to 0.2. 0.01 (Round the answer to 2 decimals) (Round the answer to 2 decimals) (Round the answer to 2 decimals) Total 1

Question 6 The number of credit cards in the wallet of a randomly selected person varies from 0 to 6. The probability distribution of the number of credit cards, X, is as follows: 0 1 2 3 0.33 Xi P(X = x₁) 0.03 ■ X=5 P(X=4)=0.2 P(X=2) |X=5 P(X=4)=0.2 P(X=2) 0.11 X=5 P(X=4)=0.2 P(X=2) 1. Use the random variable notation to express symbolically each of the following: An event in which the number of credit cards is exactly 5. 0.17 4 0.2 b. P(0 ≤ x ≤ 1) = c. P(X > 1) 5 0.15 The probability that the number of credit cards is exactly 2. 2. Use the above probability distribution table to find the following: a. P(3 < X <5) 6 The probability that the number of credit cards is exactly 4 is equal to 0.2. 0.01 (Round the answer to 2 decimals) (Round the answer to 2 decimals) (Round the answer to 2 decimals) Total 1

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question 6 The number of credit cards in the wallet of a randomly selected person varies from 0 to 6. The probability distribution of the number of credit cards, X, is as follows: 0 1 2 3 0.03 0.17 Xi P(X = x₂) X=5 P(X=4)=0.2 P(X=2) |X=5 P(X=4)=0.2 P(X=2) 0.11 X=5 P(X=4)=0.2 P(X=2) 0.33 4 1. Use the random variable notation to express symbolically each of the following: An event in which the number of credit cards is exactly 5. 0.2 = 5 0.15 2. Use the above probability distribution table to find the following: a. P(3 < X < 5) b. P(0 < X < 1) c. P(X > 1) The probability that the number of credit cards is exactly 2. 6 The probability that the number of credit cards is exactly 4 is equal to 0.2. 0.01 (Round the answer to 2 decimals) (Round the answer to 2 decimals) (Round the answer to 2 decimals) Total 1
Transcribed Image Text:Question 6 The number of credit cards in the wallet of a randomly selected person varies from 0 to 6. The probability distribution of the number of credit cards, X, is as follows: 0 1 2 3 0.03 0.17 Xi P(X = x₂) X=5 P(X=4)=0.2 P(X=2) |X=5 P(X=4)=0.2 P(X=2) 0.11 X=5 P(X=4)=0.2 P(X=2) 0.33 4 1. Use the random variable notation to express symbolically each of the following: An event in which the number of credit cards is exactly 5. 0.2 = 5 0.15 2. Use the above probability distribution table to find the following: a. P(3 < X < 5) b. P(0 < X < 1) c. P(X > 1) The probability that the number of credit cards is exactly 2. 6 The probability that the number of credit cards is exactly 4 is equal to 0.2. 0.01 (Round the answer to 2 decimals) (Round the answer to 2 decimals) (Round the answer to 2 decimals) Total 1
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