Question 6 Suppose you have to use spherical coordinates to evaluate the triple integral fffz dv w zdV where D is the solid region that lies inside the cone z = √2 + y2 and inside the sphere 22 + y2 + Then the triple ingral in terms of spherical coordinates is given by =289
Question 6 Suppose you have to use spherical coordinates to evaluate the triple integral fffz dv w zdV where D is the solid region that lies inside the cone z = √2 + y2 and inside the sphere 22 + y2 + Then the triple ingral in terms of spherical coordinates is given by =289
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Question 6
Suppose you have to use spherical coordinates to evaluate the triple integral
= dV where D is the solid region that lies inside the cone z = √² + y² and inside the sphere 2² + y² + 2² = 289
D
Then the triple ingral in terms of spherical coordinates is given by
Select all that apply
o fffz dv=
zdV=
2x
-1²* 15/4 617 ² sing dp do d
do
o
- fff z dv =
z dv==
!!!=
Il
D
-1/4 √2 17³ cos sin dp de dó
2 17
= 1² */4 ¹7 pcos p dp do de
(2 17
- 10/²2 12² 11²/
z dv=
3 cos sin dp o
qua
de do
2 17
- [[] = dv = √² + √ =/ 4 [ ²7/0 ³ €
-1² 1/4 6¹7 8³ cos sind dp do de
z dV==
17
fff = d = "/"p³ cos sind dp do de
zdV ==
2/4 17
fffz dv=²* [*/^ ["p³ cossin & do de dó
zdV=
2x **/2 17
- [[] = dv = √² + √2/1² (²7², ³ .
-6²th p³ cos osin o dp do do
dV=
D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F579b134a-c790-4337-9259-0ba12f2f85ea%2F3d50d453-4135-4f64-afa8-b6c4fcdc3ac5%2Fgyfhklw_processed.png&w=3840&q=75)
Transcribed Image Text:Question 6
Suppose you have to use spherical coordinates to evaluate the triple integral
= dV where D is the solid region that lies inside the cone z = √² + y² and inside the sphere 2² + y² + 2² = 289
D
Then the triple ingral in terms of spherical coordinates is given by
Select all that apply
o fffz dv=
zdV=
2x
-1²* 15/4 617 ² sing dp do d
do
o
- fff z dv =
z dv==
!!!=
Il
D
-1/4 √2 17³ cos sin dp de dó
2 17
= 1² */4 ¹7 pcos p dp do de
(2 17
- 10/²2 12² 11²/
z dv=
3 cos sin dp o
qua
de do
2 17
- [[] = dv = √² + √ =/ 4 [ ²7/0 ³ €
-1² 1/4 6¹7 8³ cos sind dp do de
z dV==
17
fff = d = "/"p³ cos sind dp do de
zdV ==
2/4 17
fffz dv=²* [*/^ ["p³ cossin & do de dó
zdV=
2x **/2 17
- [[] = dv = √² + √2/1² (²7², ³ .
-6²th p³ cos osin o dp do do
dV=
D
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