Question 6 of 10, Step 1 of 1 a varies directly as the square of b and inversely as the cube of c. If a = 171 when b = 8 and c = 9, find a if b = 9 and c = 6. Round your answer to two de places if necessary. Answer 5/10 Correct AM Keyboard:
Question 6 of 10, Step 1 of 1 a varies directly as the square of b and inversely as the cube of c. If a = 171 when b = 8 and c = 9, find a if b = 9 and c = 6. Round your answer to two de places if necessary. Answer 5/10 Correct AM Keyboard:
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![**Question 6 of 10, Step 1 of 1:**
*A* varies directly as the square of *b* and inversely as the cube of *c*. If *a* = 171 when *b* = 8 and *c* = 9, find *a* if *b* = 9 and *c* = 6. Round your answer to two decimal places if necessary.
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**Answer:**
\[ a = \] [Input box]
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No graphs or diagrams are present in this question.
*Note: This question involves solving a variation problem using the relationship \( a = k \frac{b^2}{c^3} \) where you first find the constant \( k \) using the given values and then use that \( k \) to calculate the new value of \( a \) with the new values of \( b \) and \( c \).*](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F60bf36b7-aa95-436f-b788-de87d7d79004%2F70406258-6614-404d-8411-05fb26031b0f%2Fdpbighs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 6 of 10, Step 1 of 1:**
*A* varies directly as the square of *b* and inversely as the cube of *c*. If *a* = 171 when *b* = 8 and *c* = 9, find *a* if *b* = 9 and *c* = 6. Round your answer to two decimal places if necessary.
---
**Answer:**
\[ a = \] [Input box]
---
No graphs or diagrams are present in this question.
*Note: This question involves solving a variation problem using the relationship \( a = k \frac{b^2}{c^3} \) where you first find the constant \( k \) using the given values and then use that \( k \) to calculate the new value of \( a \) with the new values of \( b \) and \( c \).*
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