Question 6 Let n, m, and p be integers such that p = n + m. Prove by contradiction that if p is odd, then n or m must be odd (i.e. they can't both be even) and n or m must be even (i.e. they can't both be odd).

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question 6
Let n, m, and p be integers such that p = n + m. Prove by contradiction that if p is odd,
then n or m must be odd (i.e. they can't both be even) and n or m must be even (i.e.
they can't both be odd).
Transcribed Image Text:Question 6 Let n, m, and p be integers such that p = n + m. Prove by contradiction that if p is odd, then n or m must be odd (i.e. they can't both be even) and n or m must be even (i.e. they can't both be odd).
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