Question 6 < > How many different 3 card hands can be dealt from a deck of 52 cards? Your answer is :
Question 6 < > How many different 3 card hands can be dealt from a deck of 52 cards? Your answer is :
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![**Question 6:**
**How many different 3 card hands can be dealt from a deck of 52 cards?**
*Your answer is:* [Input box]
This question asks about combinations, specifically how to determine the number of possible 3-card hands selected from a standard deck of 52 playing cards. To solve this, you would use the combination formula:
\[ C(n, k) = \frac{n!}{k!(n-k)!} \]
where \( n \) is the total number of items to choose from, \( k \) is the number of items to choose, and \( ! \) denotes factorial. In this case, \( n = 52 \) and \( k = 3 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc614d0cc-0eed-46aa-b3af-63162652eb2c%2Fdaf489af-5bda-4ea3-b2dc-255318500a42%2Fflro6pw_processed.png&w=3840&q=75)
Transcribed Image Text:**Question 6:**
**How many different 3 card hands can be dealt from a deck of 52 cards?**
*Your answer is:* [Input box]
This question asks about combinations, specifically how to determine the number of possible 3-card hands selected from a standard deck of 52 playing cards. To solve this, you would use the combination formula:
\[ C(n, k) = \frac{n!}{k!(n-k)!} \]
where \( n \) is the total number of items to choose from, \( k \) is the number of items to choose, and \( ! \) denotes factorial. In this case, \( n = 52 \) and \( k = 3 \).
Expert Solution

Step 1
solution:
Total number of cards =52
Then,
Total number of ways to dealt 3 different cards= 52C3
=22100.
Step by step
Solved in 2 steps

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