Question 6 Consider two groups Q[x] (defined in Question 3(v)) and Q, both under the usual + of polynomials and numbers, respectively. Prove that these two algebraic structures (groups?) are not isomorphic. (Hint: Note these structures happen to also be Q-vector spaces under the right choice of operations, and these spaces have different dimension. However, you cannot appeal to linear algebra, because we are not viewing these objects as vector spaces, but maybe this will give you an idea. Think of some property that holds in, e.g., Q but not in Q[x] or vice versa, and so that this property uses only the group operation in its description and is independent of notation. )

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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This Question really confuses me. It's clear that it's not isomorphic since the two groups have different dimensions but how do I prove that?

(The set Q(x) of all polynomials in x with coefficients from Q and under the usual addition of polynomials is the group defined in question 3(v))

Question 6 Consider two groups Q[x] (defined in Question 3(v)) and Q, both under the usual
+ of polynomials and numbers, respectively. Prove that these two algebraic structures (groups?)
are not isomorphic. (Hint: Note these structures happen to also be Q-vector spaces under the
right choice of operations, and these spaces have different dimension. However, you cannot
appeal to linear algebra, because we are not viewing these objects as vector spaces, but maybe
this will give you an idea. Think of some property that holds in, e.g., Q but not in Q[x] or
vice versa, and so that this property uses only the group operation in its description and is
independent of notation. )
Transcribed Image Text:Question 6 Consider two groups Q[x] (defined in Question 3(v)) and Q, both under the usual + of polynomials and numbers, respectively. Prove that these two algebraic structures (groups?) are not isomorphic. (Hint: Note these structures happen to also be Q-vector spaces under the right choice of operations, and these spaces have different dimension. However, you cannot appeal to linear algebra, because we are not viewing these objects as vector spaces, but maybe this will give you an idea. Think of some property that holds in, e.g., Q but not in Q[x] or vice versa, and so that this property uses only the group operation in its description and is independent of notation. )
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