QUESTIÓN 6Assume that a researcher randomly selects 14 newborn babies and counts the number of girls selected, x. Theprobabilities corresponding to the 14 possible values of x are summarized in the given table. Answer thequestion using the table.Probabilities of Girlsx(girls) P(x) x(girls)| P(x) x(girls) P(x)0.0610.0000.1221010.00160.183110.02220.00670.209120.00630.0220.183130.00140.06190.122140.000Find the probability of selecting exactly 5 girls.O 0.022O 0.122O 0.061O 0.001

We want exact probability of x=5

Answered: QUESTION 6 Assume that a researcher…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Please solve 6 a, b and c
I'm pretty sure that the answer for part A can be found by using the normalCDF function on my TI-84 Calculator. Plugging in 60 as the Lower Bound, 90 as the Upper Bound, 65 for the mean, and 13 for the Standard Deviation results in a probability of 0.6225. However, I tried the same for part B, plugging in 0 as the Lower Bound, 20 as the Upper Bound, 65 for the mean, and 13 for the Standard Deviation. This resulted in a probability of 0.0002683, which doesn't seem right to me. I would greatly appreciate it if someone could double check my reasoning and if wrong, explain which formula I should use to get the correct answer for part B.
According to Trains, Trains Trains, trains in Jacksonville had an on-time percentage of 79.0% in 2019. Suppose that 4 trains are randomly selected from 2019 and the number of on-time trains X is recorded. What is the probability that 3 trains are on time? Write it as 0.5^2 (even if the exponent is 1 or 0 to show the pattern 0.79^30.21^14What is the probability the other 1 trains are NOT on time? Write it as 0.5^2 (even if the exponent is 1 or 0 to show the pattern 0.21^140.79^3How many possible options are there that 3 trains are on time? i.e. think about 1st flight on time, or the second, or the third, etc. Use picture above! 40.79^30.21^1You would then multiply all answers together to find the probability.
Suppose that E and F are two events and that P(E and F)=0.48, P(F)=0.55, and P(E)=0.5. What is P(F |E)?
I wonder how do we get the number 22 as I highlight? Please help me to explain. Thank you!
I ONLY need help with parts (c) and (d) on this Intro to probability and statistics homework problem. Below the homework problem is the answers from the textbook. Make sure your handwriting is neat and readable.
let A and B be two independent events if P(A)=.74 and P(B)=.23 what is P(A|B)
PLEASE ANSWER (d) ONLY. a-c have been answered. Suppose a dresser drawer has blue shirts, yellow shirts, red shirts, and green shirts so that if a shirt is pulled from the drawer at random, each color has an equal chance of being drawn. P(Green) = P(Blue) = P(Red) = P(Yellow) = ¼. Complete parts (a) – (d) to create a probability distribution for the number of yellow shirts if two shirts are pulled from the drawer at random (replacing the shirt after each draw). (a) List each possible outcomefor the colors of the shirts if two shirts are drawn randomly from the drawer. Green, Blue, / Green, Red, / Green, Yellow, / Green, Green Blue, Green / Blue, Blue / Blue, Red / Blue, Yellow Red, Green / Red, Blue / Red, Red / Red, Yellow Yellow, Green / Yellow, Blue / Yellow, Red / Yellow, Yellow (b) List the possible events for the number of yellow shirtsif two shirts are drawn randomly from the drawer. Green, Yellow / Blue, Yellow / Red, Yellow Yellow, Yellow (c) Find the probability of each…
42% of adults say cashews are their favorite kind of nut. You randomly select 12 adults and ask each to name his or her favorite nut. Find the probability that the number who say cashews are their favorite nut is (a) exactlythree, (b) at least four, and (c) at most two. If convenient, use technology to find the probabilities. (a) P(3)= (b) P(x>_4)= c) P(x<_2)=
A recent poll has suggested that 61 % of Canadians will be spending money - decorations, halloween treats, etc. - to celebrate Halloween this year. 23 Canadians are randomly chosen, and the number that will be spending money to celebrate Halloween is to be counted. This count is represented by the random variable X. Part (a) Compute the probability that 16 of these Canadians indicate they will be spending money to celebrate Halloween. P(X16) = (use four decimals in your answer) Part (b) Compute the probability that between 7 and 16 of these Canadians, inclusive, indicate they will be spending money to celebrate Halloween. P(7< X < 16) = (use four decimals in your answer) Part (c) How many of the 23-Canadians randomly chosen would you expect to indicate they will be spending money to celebrates Halloween? Compute the standard deviation as well.. E(X) = 4x = SD(X)=ox= (use two decimals in your answer) (use two decimals in your answer) Part (d) Compute the probability that the 14-th…
Results from trials for a new pill for sleeping are given in this table. slept better (B) no improvement (N) sleeping pill (S) 144 21 sugar tablet (T) 55 89 What is the probability that the subjects slept better if they took the sleeping pill = P(B|S) ? What is the probability that the subjects took the tablet if they slept better = P(T|B)? Give your answer as a fraction.
Suppose that in a year of 365 days, it rains on 62 days. There is lightning on 13 days. There is both lightning and rain on 12 days. Compare the chance that a rainy day has lightning to the chance that a day with lightning has rain. Show your work here P(lightning | rain) = P(rain | lightning)

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