Question 6:An experiment concerning the calculation of a confidence interval for the population proportion isrepeated from a previous trial. The sample proportion changed from 0.78 to 0.81 between the first andsecond runs of this experiment, and all other measures stayed the same. How would the width of theresulting confidence interval change?Answer:

Given: Old sample proportion = 0.78 New sample proportion = 0.81

Answered: Question 6: An experiment concerning…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question # 11: Using the data in question 9 (I just resubmitted to Bartleby), calculate the 95% confidence interval for the mean ACT score based on the t-distribution. 29, 26, 13, 23, 23, 25, 17, 22, 17, 19, 12, 26, 30, 30, 18, 14,12, 26, 17, 18 Choose the following: A. 18.07 to 23.63 B. -∞ to 23.15 C. 18.22 to 23.48 D. -∞ to 23.05
QUESTION 26 The waiting time (in minutes) of customers at a fast food outlet is normally distributed. A random sample of 15 customers is selected and the 99% confidence interval for the population mean waiting time is obtained as (1.83,2.59). Find the standard deviation used to construct the 99% confidence interval. Round your answer to three decimal places.
Question 2 Express the confidence interval 24.3 % < p < 41.3 % in the form of p ± ME.
Question 5 A common claim is that garlic lowers cholesterol levels. In a test of the effectiveness of garlic, 45 subjects were treated with doses of raw garlic, and their cholesterol levels were measured before and after the treatment. The changes in their levels of LDL cholesterol (in mg/mL) have a mean of 4.94 mg/mL and a standard deviation of 18.51 mg/mL. Construct a 95% confidence interval for the average net change in LDL cholesterol after the garlic treatment. i. Procedure: Select an answer Select an answer One proportion Z procedure One mean T procedure One mean Z procedure One variance x² procedure ii. Assumptions: (select everything that applies) Simple random sample Sample size is greater than 30 Population standard deviation is unknown Population standard deviation is known The number of positive and negative responses ar Normal population iii. Unknown parameter: Select an answer Select an answer u, population mean o², population variance p, population proportion
QUESTION 3 The GPAs of nursing students (p1) were compared to GPAs of student-athletes (p2) were compared. Of a sample of 400 randomly and independently selected nursing students, 75% were placed on honor roll. Of a sample of 100 athletes, 80% of the students were placed on honor roll. Calculated the UPPER bound of the 95% confidence interval for the two samples. Round to the nearest hundredth.
QUESTION 1 A hardware store determined the current balances for a random sample of 100 customers with non-zero balances. The sample mean of the amount owed was $100.00 and the standard deviation was $25. Use the assumption that the sample standard deviation is equal to the population standard deviation. You are asked to find a confidence interval for the average amount owed by all customers with a non-zero balance. Which Minitab procedure would be most appropriate to use for this task? O Power and Sample Size/1-Sample Z O Power and Sample Size/Sample Size for Estimation/1-Sample Z O Basic Statistics/1-Sample Z O Basic Statistics/1-Sample t
QUESTION 23 A Hi-Tech company has introduced a new fash disk. Some dealers and customers have complained that some of the new disks are defective. In order to investigate this the company randomly tested 300 disks and found that 30 were defective. A 99% confidence interval for the proportion of all fash disks that are defective was (5.54%, 14.46%). Which one of the following statements is the correct interpretation of the results? We are 99% confident that (5.54%, 14.46%) contains the true population proportion. O None of these are true. O With probability 99%, the confidence interval (5.54%, 14.46%) contains the true population proportion. Of all the fash disks 99% of the fash disks in the sample are defective between 5.54% and 14.46%.
Question 1: A confidence interval is calculated after running a two-sample z-test for proportions, yielding the result: [0.01, 0.14]. Determine the margin of error for this interval. Answer:
Question 5, 8.2.34
#20
question 3
QUESTION 1 A company claims that the mean weight of coffee in its 16-ounce bags is 16.05 ounces. Consumer advocates group constructed the following 95% confidence interval (16.09, 16.12). Based on this interval, do you think that the company's claim is plausible at the 5% significance level? 16.05 lies in the interval (16.09, 16.12), so we do not reject the manufacturer's claim. 16.05 does not lie in the interval (16.0, 16.2), so we reject the manufacturer's claim. Not enough information to answer the question. 16.05 does not lie in the interval (16.09, 16.12), so we reject the company's claim.

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Question 6: An experiment concerning the calculation of a confidence interval for the populat repeated from a previous trial. The sample proportion changed from 0.78 to 0.81 second runs of this experiment, and all other measures stayed the same. H resulting confidence interval change?