QUESTION 6 A person is standing on top of a 20 m wall. They throw a ball horizontally at 15 m/s. The ball lands after 2 seconds. They throw a second ball horizontally at 30 m/s. How long does it take the second ball to hit the ground? A, 4 seconds B, 2 seconds C. 2.83 seconds D, 1 second

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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Question 6**

A person is standing on top of a 20 m wall. They throw a ball horizontally at 15 m/s. The ball lands after 2 seconds. They throw a second ball horizontally at 30 m/s. How long does it take the second ball to hit the ground?

- A. 4 seconds
- B. 2 seconds
- C. 2.83 seconds
- D. 1 second
Transcribed Image Text:**Question 6** A person is standing on top of a 20 m wall. They throw a ball horizontally at 15 m/s. The ball lands after 2 seconds. They throw a second ball horizontally at 30 m/s. How long does it take the second ball to hit the ground? - A. 4 seconds - B. 2 seconds - C. 2.83 seconds - D. 1 second
Expert Solution
Step 1

When a ball is projected from height H, the time taken to reach the ball to the ground could be calculated  by the second equation of motion as follows: 

Sy = uy . t + 12 ay t2 h = 0 + 12 g t2    (because uy = 0) t = 2hg        ..............(1)

 

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