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Question 6: a) Find the closed loop transfer function:... b) Determine the range of k. c) what is the type of the system....... f) Find the steady-state errors at k-22,when r(t)= 1.5 tu(t) step input is applied:.. g) Find the steady-state errors at k-22,when 1.5tu(t) ramp input is applied:.. C(s) R(s) s(s+2)(s+5) 1+ s(s+2)(s+5). S

Question 6: a) Find the closed loop transfer function:... b) Determine the range of k. c) what is the type of the system....... f) Find the steady-state errors at k-22,when r(t)= 1.5 tu(t) step input is applied:.. g) Find the steady-state errors at k-22,when 1.5tu(t) ramp input is applied:.. C(s) R(s) s(s+2)(s+5) 1+ s(s+2)(s+5). S

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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I want answers only for last two questions and I attaced the answers for the first 3 questions for help
Question 6: a) Find the closed loop transfer function:.. b) Determine the range of k... c) what is the type of the system....... f) Find the steady-state errors at k-22,when r(t)= 1.5 tu(t) step input is applied: g) Find the steady-state errors at k=22,when 1.5tu(t) ramp input is applied::...... C(s) R(s) 1 s(s+2)(s+5) 1 1+ (s(s+2) (5+5))
Transcribed Image Text:Question 6: a) Find the closed loop transfer function:.. b) Determine the range of k... c) what is the type of the system....... f) Find the steady-state errors at k-22,when r(t)= 1.5 tu(t) step input is applied: g) Find the steady-state errors at k=22,when 1.5tu(t) ramp input is applied::...... C(s) R(s) 1 s(s+2)(s+5) 1 1+ (s(s+2) (5+5))
student ID: 180502934 Department: Computer engineering a) From the question: C(S) R(S) = S(S+2) (S+5) T + s 1+ S [s(s+2)(S+5), . Let we include parameter K C(s) K = R(S) REES RECEIREST (1) T 1 FAW FINEST C(S) K = R(S) S[(S+2)(S+S) + K] . Closed loop transfer function: C(S) K R(S) S[S+75+10+ K b) The general form of closed transfer function is C(S) G(S) R(S) 1+G(S)H(S) By comparing (1) & (2) (2) K G(S)H(S) = S(S+2) (S+5) K S=(5+2)(S+5) Characteristic equation 1+G(S) H(S)=0 K 1+ (5+2)(5+5) = 0 S² +75 +K+10=0 (3) Accessibility: Unavailable. 06: I student ID: 180502934 Department: Computer engineering By Routh table, S² S¹ S" 1 k+10 1 7 K+10 k+10 >0 k>-10 -10 <k<∞ range of K.Value C) The number of the poles at the region in open loop transfer function G(S) H(S) is called as the type of system K (S+2) (S+5) As there're no poles at the region, the type of the system is Zero (Type-0 system) G(S)H(S) = 77°F
Transcribed Image Text:student ID: 180502934 Department: Computer engineering a) From the question: C(S) R(S) = S(S+2) (S+5) T + s 1+ S [s(s+2)(S+5), . Let we include parameter K C(s) K = R(S) REES RECEIREST (1) T 1 FAW FINEST C(S) K = R(S) S[(S+2)(S+S) + K] . Closed loop transfer function: C(S) K R(S) S[S+75+10+ K b) The general form of closed transfer function is C(S) G(S) R(S) 1+G(S)H(S) By comparing (1) & (2) (2) K G(S)H(S) = S(S+2) (S+5) K S=(5+2)(S+5) Characteristic equation 1+G(S) H(S)=0 K 1+ (5+2)(5+5) = 0 S² +75 +K+10=0 (3) Accessibility: Unavailable. 06: I student ID: 180502934 Department: Computer engineering By Routh table, S² S¹ S" 1 k+10 1 7 K+10 k+10 >0 k>-10 -10 <k<∞ range of K.Value C) The number of the poles at the region in open loop transfer function G(S) H(S) is called as the type of system K (S+2) (S+5) As there're no poles at the region, the type of the system is Zero (Type-0 system) G(S)H(S) = 77°F
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