Question 5. The basic chemical reaction involved in a typical wet process for SO₂ removal (emission of SO₂ to atmosphere is a main cause for formation of acid rain) can be explained in the following: AĤ,= -47.3 kJ/mol, SO₂ (g) + H₂O (1) + (NH4)2SO3(aq) 2 NH4HSO3(aq) = where AĤ, is the standard heat of this reaction. A gaseous mixture of N₂ and SO₂ (0.60 mol %) fed to a reactor at a rate of 25000 mol/h at 50°C is treated with the above process. An aqueous stream which contains 15.0 mol % (NH4)2SO3 is sent into the reactor at 25°C. Through this process, 93% of the SO₂ can be converted to NH4HSO3, and the molar ratio of NH4HSO3 to (NH4)2SO3 is 0.65 in Stream c. (i) Calculate flow rates for Streams a, b, and c in mol/h. (ii) What will be the required rate of heat removal (or addition) in kJ/h or kW for this process? You can assume that all aqueous streams have a specific heat capacity of 4.12 J/g.°C, and evaporation of water may be neglected in your calculation. N₂, SO₂, 50°C (NH4)2SO3 (aq), 25°C Gas SO₂ SO₂ N₂ To save your time in calculation, some specific enthalpy data of gaseous compounds over the related temperature ranges have been pre-calculated and tabulated in the following table: N₂ 3 a Reactor b C Specific enthalpy change (T in °C) 50 ▲Â = §C„dT =1.01kJ/mol 25 35 AĤ= fcdT=0.40 kJ/mol 25 50 AĤ=fc₂dT= jc,dr 25 35 AĤ = §CÂdT = 0.292 kJ/mol 25 N₂, SO2, 35°C NH4HSO3(aq) & (NH4)2SO3 (aq), 35°C = 0.73 kJ/mol
Question 5. The basic chemical reaction involved in a typical wet process for SO₂ removal (emission of SO₂ to atmosphere is a main cause for formation of acid rain) can be explained in the following: AĤ,= -47.3 kJ/mol, SO₂ (g) + H₂O (1) + (NH4)2SO3(aq) 2 NH4HSO3(aq) = where AĤ, is the standard heat of this reaction. A gaseous mixture of N₂ and SO₂ (0.60 mol %) fed to a reactor at a rate of 25000 mol/h at 50°C is treated with the above process. An aqueous stream which contains 15.0 mol % (NH4)2SO3 is sent into the reactor at 25°C. Through this process, 93% of the SO₂ can be converted to NH4HSO3, and the molar ratio of NH4HSO3 to (NH4)2SO3 is 0.65 in Stream c. (i) Calculate flow rates for Streams a, b, and c in mol/h. (ii) What will be the required rate of heat removal (or addition) in kJ/h or kW for this process? You can assume that all aqueous streams have a specific heat capacity of 4.12 J/g.°C, and evaporation of water may be neglected in your calculation. N₂, SO₂, 50°C (NH4)2SO3 (aq), 25°C Gas SO₂ SO₂ N₂ To save your time in calculation, some specific enthalpy data of gaseous compounds over the related temperature ranges have been pre-calculated and tabulated in the following table: N₂ 3 a Reactor b C Specific enthalpy change (T in °C) 50 ▲Â = §C„dT =1.01kJ/mol 25 35 AĤ= fcdT=0.40 kJ/mol 25 50 AĤ=fc₂dT= jc,dr 25 35 AĤ = §CÂdT = 0.292 kJ/mol 25 N₂, SO2, 35°C NH4HSO3(aq) & (NH4)2SO3 (aq), 35°C = 0.73 kJ/mol
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:Question 5. The basic chemical reaction involved in a typical wet process for SO₂ removal (emission
of SO₂ to atmosphere is a main cause for formation of acid rain) can be explained in the following:
AĤ=-47.3 kJ/mol,
SO₂ (g) + H₂O (1) + (NH4)2SO3(aq) 2 NH4HSO3(aq)
where AF, is the standard heat of this reaction. A gaseous mixture of N₂ and SO₂ (0.60 mol %) fed to a
reactor at a rate of 25000 mol/h at 50°C is treated with the above process. An aqueous stream which
contains 15.0 mol% (NH4)2SO3 is sent into the reactor at 25°C. Through this process, 93% of the SO₂
can be converted to NH4HSO3, and the molar ratio of NH4HSO3 to (NH4)2SO3 is 0.65 in Stream c. (i)
Calculate flow rates for Streams a, b, and e in mol/h. (ii) What will be the required rate of heat removal
(or addition) in kJ/h or kW for this process? You can assume that all aqueous streams have a specific
heat capacity of 4.12 J/g °C, and evaporation of water may be neglected in your calculation.
N2, SO2, 50°C
(NH4)2SO3 (aq), 25°C
Gas
SO₂
SO₂
N₂
=
a
N₂
To save your time in calculation, some specific enthalpy data of gaseous compounds over the related
temperature ranges have been pre-calculated and tabulated in the following table:
Reactor
b
C
Specific enthalpy change (T in °C)
50
=jc,dT=
AĤ = [C,dT
25
35
AĤ = C,dT = 0.40 kJ/mol
25
50
AĤ = [C₁dT=0.73 kJ/mol
25
= 1.01 kJ/mol
N₂, SO2, 35°C
NH4HSO3(aq) & (NH4)2SO3 (aq), 35°C
35
▲Â = §C₁dT = 0.292 kJ/mol
25
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