Question 5. Let p= 3 (mod 4) be a prime. Assume that a is an integer such that the order of a is (p-1)/2, i.e., a(p-¹)/2 = 1 (mod p) but a" # 1 (mod p) for any n with 1 ≤ n < (p-1)/2. Prove that – a is a primitive root modulo p.

Q: What is the result when you square the quantity -3.

A: Square means just multiply the number to itself.

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Q: (b) E, 5 100 «j=0

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Q: 5 x + 8 = x + 9 What is the value of x?

A: It is given that, 5 x + 8 = x + 9  We have to find the value of x.

Q: Giventhat a = (2, 2), b = (-2, 5), and c = = (-4, -3), find the number. (Round your answer to one…

A: As we know that the component of a vector a along the direction of vector b is:

Q: z + 2 8z - 3 4-

A: First cross multiply the terms and then follow the algebraic operation.

Q: What is the value of 153? Enter a, b, c, d, or e. a. 1 b. i 4 c. - 1 d. -i e. 0

A:

Q: 7? x (-4)'

A:

Q: How would you solve this

A: How to evaluate 560.76

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Q: What is wrong with the equation?

A: The above solution is incorrect.

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