Question 5: The following function is supposed to reverse a singly-linked list. Fill in the blanks. Assume the constructors ‘make-my-list' and 'my-cons', the accessors ‘my-car’ and 'my-cdr', and the helper 'is-empty' are given and are the same ones used in lab 4. (defun rev-11 (a &optional (b ...)) (if (is-empty ...) (rev-11 (my-cdr .) (... (my-car a) ...))))

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(Q5) This is a Data Structures problem and the programming language used is Lisp. Solve the question we detailed steps and make it concise and easy to understand. Please and thank you.

Question 5:
The following function is supposed to reverse a singly-linked list. Fill in the
blanks.
Assume the constructors 'make-my-list' and 'my-cons', the accessors 'my-car'
and 'my-cdr', and the helper ‘is-empty' are given and are the same ones used in
lab 4.
(defun rev-11 (a &optional (b ...))
(if (is-empty ...)
(rev-11 (my-cdr .) (... (my-car a) ...))))
Transcribed Image Text:Question 5: The following function is supposed to reverse a singly-linked list. Fill in the blanks. Assume the constructors 'make-my-list' and 'my-cons', the accessors 'my-car' and 'my-cdr', and the helper ‘is-empty' are given and are the same ones used in lab 4. (defun rev-11 (a &optional (b ...)) (if (is-empty ...) (rev-11 (my-cdr .) (... (my-car a) ...))))
Expert Solution
Step 1: Introduction:

In Lisp , simple list is called a single linked list which consists a chain of records. In this Cons is used to record the data with two important components. Lists can share their parts within the code and it consist sequences of numbers.

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