QUESTION 5 The following data were collected for the reaction at 580 K 2HI (g) → H₂(8) + 12(8) t(s) 0 1000 2000 3000 4000 [HI]/ (mol dm³) 1.00 0.112 0.061 0.041 0.031 (a) What is the order of reaction. Choose one. Ooth order 1st order 2nd order O 3rd order QUESTION 6 (b) use data above to calculate the rate constant. k = (mol/L, s1, L/mol/s, or L2/mol²/s). 2 s.f. normal format.
QUESTION 5 The following data were collected for the reaction at 580 K 2HI (g) → H₂(8) + 12(8) t(s) 0 1000 2000 3000 4000 [HI]/ (mol dm³) 1.00 0.112 0.061 0.041 0.031 (a) What is the order of reaction. Choose one. Ooth order 1st order 2nd order O 3rd order QUESTION 6 (b) use data above to calculate the rate constant. k = (mol/L, s1, L/mol/s, or L2/mol²/s). 2 s.f. normal format.
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![QUESTION 5
The following data were collected for the reaction at 580 K
2HI (g) → H₂(8) + 12(8)
t(s)
0
1000
2000
3000
4000
[HI]/ (mol
dm³)
1.00
0.112
0.061
0.041
0.031
(a) What is the order of reaction. Choose one.
Ooth order
1st order
2nd order
O 3rd order
QUESTION 6
(b) use data above to calculate the rate constant.
k =
(mol/L, s1, L/mol/s, or L2/mol²/s). 2 s.f. normal format.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F334e2f07-82c9-488f-aeb5-259bf8d2ec1e%2F06335b3b-e71c-4abf-bb8a-86add22aac62%2F3zuncsp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:QUESTION 5
The following data were collected for the reaction at 580 K
2HI (g) → H₂(8) + 12(8)
t(s)
0
1000
2000
3000
4000
[HI]/ (mol
dm³)
1.00
0.112
0.061
0.041
0.031
(a) What is the order of reaction. Choose one.
Ooth order
1st order
2nd order
O 3rd order
QUESTION 6
(b) use data above to calculate the rate constant.
k =
(mol/L, s1, L/mol/s, or L2/mol²/s). 2 s.f. normal format.
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