QUESTION 5 For the given frequency distribution, calculate the mean of X. Class Limit 1-7 8-14 15-21 22-28 29-35 Frequency 8. 12 18 12 10 17.48 O 19.69 O18.47 O 20.34

Q: 64y2+7=32

A: 64y2+7=32

Q: 1+2x=77

A:

Q: Find A. A= (4A)-¹ = 3 2 22

A:

Q: -12+(4• 3) (-) I 2-14 - 3)ENTER

A:

Q: Todt 5(-37+4)

A: Given,   ∫  -3t+410dt

Q: 2x=axz

A: Given equation is 2x=axz

Q: Зх + 9 6x P R

A: AAS criteria: If two angles and an opposite side of one triangle are congruent to the two angles and…

Q: ^2 for the scor

A: to find (sum of x)2 x= 1,5,4

Q: -3w+5=23

A:

Q: (-12)+7

A: To simplify any expression involving numbers we need to use the BODMAS rule which specifies the…

Q: Find

A:

Q: Vs-+ 12²

A: To determine:

Q: -4d = -64

A: Given  -4d=-64

Q: 1+n=15

A: -1+n=15

Q: Find fre dz |2e*dx

A:

Q: -5 -2 1

A:

Q: 10 = 2(p + -4)

A: Given  10 = 2(p + -4) p =?

Q: -8 = 6+n

A:

Q: Q5/ Find A-в, if: 1 2 3 - 2 1 B = 2 A = 2 -1 0 1 3 - 1

A:

Q: p dx. -3x (h)

A:

Q: A+12=13

A: Given,   A+12=13     We will solve it for the value of A

Q: 2t2 – 100 = 0 %3D

A: The solution is, t = ±5√2  The detailed solution is as follows below:

Q: Find L s²-8

A:

Q: Find

A: We know that,                         ∫1xdx=lnx+ c We need to find  ∫4xdx

Q: 2+36=38

A: Given 2+ 36 = 38  Yes the given statement is true .

Q: dx 4е2я — 8ет + 5

A: This question can be solved using the concept of special integrals.

Q: Find x. X+4

A:

Q: -4c +2 ≥10

A: The given inequality is: -4c+2≥10

Q: 3=-6+r

A:

Q: z? - 34z + 818 = 0

A:

Q: A = p + prt for r ( banking)

A:

Q: D-G please

A: Given information- Population mean, μ = 8 minutes Sample size, n = 14 Sample mean, x-bar = 9.1…

Q: N+2=4

A: The value is:-

Q: Q3 a and b

A: As you asked for only question number 3 both a. And b. So here it is.

Q: 15 + q/6 =-21

A: To find the value of q, 15 + q/6 = -21 => q/6 = -21 - 15