Question 5: (Consider yielding & rupture limit states only) An L5 x 5 x ½ tension member of A242 steel is connected to a gusset plate with six 4-inch-diameter bolts as shown in Figure P3.3-8. If the member is subject to dead load and live load only, what is the maximum total service load that can be applied if the ratio of live load to dead load is 2.0? Use the alternative value of U from AISC Table D3.1. a. Use LRFD. b. Use ASD. L5 x 5 x 2 O O o O O O 5 spaces @ 3". = 15" 12" 12" FIGURE P3.3-8

Question 5: (Consider yielding & rupture limit states only) An L5 x 5 x ½ tension member of A242 steel is connected to a gusset plate with six 4-inch-diameter bolts as shown in Figure P3.3-8. If the member is subject to dead load and live load only, what is the maximum total service load that can be applied if the ratio of live load to dead load is 2.0? Use the alternative value of U from AISC Table D3.1. a. Use LRFD. b. Use ASD. L5 x 5 x 2 O O o O O O 5 spaces @ 3". = 15" 12" 12" FIGURE P3.3-8

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

For this Problem, kindly refer to our Textbook, Steel Design Fifth Edition by William T. Segui. For Problem 8.2-3 Page 573, if the 65kip load (service load which is 30% deadload and 70% liveload) is changed to 85kips, and the 6inches distance is also changed to 6.1inches, using plastic analysis (LRFD) calculate the magnitude (only) of the shear force at the most stressed bolt due to eccentric load? Express your answer in kips in 2 decimal places.
need answer and how to solve thank you
The tension member shown in the figure is connected to a gusset plate as shown with 1.2-inch diameter bolts. It is subjected to the dead and live loads as shown. Take Fy=33.2 ksi and Fu = 52.9 ksi. Assume Ae = An. a) Draw the critical cross-section and show its dimensions using your data. b) Determine whether this member has enough strength using LRFD and the critical ASCE 7 loading combination. 000 DL = 137 kips LL = 292 kips PL = 1 * 7
Pls answer both question, you'll get a like ty <33 Dont round off initial values, only round off in final answer ty
Answer the following for the section at Point D Only Calculate the distributed load "w" that: Will cause the section crack Will cause the reinforcement to yield. Material Properties: F'c = 5000 psi Fy = 60000 psi Es = 29000000 psi Ln = 27 ft L wl₂² 16 wl,² 14 CD L wl,2 vl₁² 10 11 win² 16 h: 28 in A=4 in² b=14 in n d: 25 in
SHOW COMPLETE SOLUTION AND DRAW ILLUSTRATION
A bolted connection between a vertical column and adiagonal brace is shown in the figure below. Theconnection consists of three 5/8-in. bolts that join two 1/4-in.end plates welded to the brace and a 5/8-in. gusset platewelded to the column. The compressive load P carried bythe brace equals 8.0k.Determine the following quantities: (a) The averageshear stress τavein the bolts, and (b) the average bearingstress σbbetween the gusset plate and the bolts. (Disregardfriction between the plates.)
The tension member shown in the figure is connected to a gusset plate as shown with 1.210-inch diameter bolts. It is subjected to the dead and live loads as shown. Take Fy = 33.29 ksi and Fu = 52.93 ksi. Assume Ae = An. a) Draw the critical cross-section and show its dimensions using your data. b) Determine whether this member has enough strength using LRFD and the critical ASCE 7 loading combination.
Give me right solution according to the question...
Problem (4): A36 steel is used for the tension member shown in Figure below. a. Determine the nominal strength based on the gross area. b. Determine the nominal strength based on the net area. PL 300mmx17mm 150 75 75 75 75 75 125 ImmmmTmm"" mmn mm mm 50mm 100mm 100mm 50mm 19mm diameter bolts Problem (5): The tension m shown in Figur
Two plates are held together by 4, 10 mm diameter bolts. If a 26 kN load is applied to the plates in shear, what is the shear stress in the bolts in MPa? Type your answer...