Question (5): A sign is supported by a pipe (see figure) having outer diameter 110 mm and inner diameter 90 mm. The dimensions of the sign are 2.0 m x 1.0 m, and its lower edge is 3.0 m above the base. Note that the center of gravity of the sign is 1.05 m from the axis of the pipe. The wind pressure against the sign is 1.5 kPa determine (a) the normal and shearing stresses located at point A (b) the principal planes and principal stresses at point A. = ? Pipe X B 1.05 m to c.g. X 2.0 m- Rose's Editing Co. A -110 mm -C 1.0 m 3.0 m B C A Section X-X ob=?
Question (5): A sign is supported by a pipe (see figure) having outer diameter 110 mm and inner diameter 90 mm. The dimensions of the sign are 2.0 m x 1.0 m, and its lower edge is 3.0 m above the base. Note that the center of gravity of the sign is 1.05 m from the axis of the pipe. The wind pressure against the sign is 1.5 kPa determine (a) the normal and shearing stresses located at point A (b) the principal planes and principal stresses at point A. = ? Pipe X B 1.05 m to c.g. X 2.0 m- Rose's Editing Co. A -110 mm -C 1.0 m 3.0 m B C A Section X-X ob=?
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:Question (5):
A sign is supported by a pipe (see figure) having outer diameter 110 mm and inner diameter 90 mm. The
dimensions of the sign are 2.0 m x 1.0 m, and its lower edge is 3.0 m above the base. Note that the
center of gravity of the sign is 1.05 m from the axis of the pipe. The wind pressure against the sign is
1.5 kPa determine (a) the normal and shearing stresses located at point A (b) the principal planes and
principal stresses at point A.
Pipe
B
X
1.05 m
to c.g.
X
-2.0 m-
Rose's
Editing Co.
A
-110 mm
-C
T
1.0 m
3.0 m
B
C
A
Section X-X
Ob=?
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