Question 5 a) i. A piece of pencil lead is connected in series with an ammeter and a power supply. The power supply is turned on. After a few minutes, although the potential difference across the pencil lead does not change, the current in the circuit increases significantly. Explain why the current increases. ii. The current / in a length of aluminum of cross-sectional area A is given by the formula I nevA e is the charge on an electron. Show that the units on the left-hand side of the equation are consistent with those on the right-hand side.

Introductory Circuit Analysis (13th Edition)
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Question 5
a)
i.
A piece of pencil lead is connected in series with an ammeter and
a power supply. The power supply is turned on. After a few
minutes, although the potential difference across the pencil lead
does not change, the current in the circuit increases significantly.
Explain why the current increases.
The current /in a length of aluminum of cross-sectional area A is
given by the formula I= nevA
ii.
e is the charge on an electron.
Show that the units on the left-hand side of the equation are
consistent with
those on the right-hand side.
Transcribed Image Text:Question 5 a) i. A piece of pencil lead is connected in series with an ammeter and a power supply. The power supply is turned on. After a few minutes, although the potential difference across the pencil lead does not change, the current in the circuit increases significantly. Explain why the current increases. The current /in a length of aluminum of cross-sectional area A is given by the formula I= nevA ii. e is the charge on an electron. Show that the units on the left-hand side of the equation are consistent with those on the right-hand side.
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