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Question 5 (1 point) 4c. A line has x-intercept 8 and z-intercept 7. Find a vector equation of the line. (x, y, z) = (-8, 0, 7) + t(8, 0, 0) (x, y, z) = (0, 0, 7) + t(-8, 0, 0) (x, y, z) = (-8, 0, 7) + t(0, 0, 7) (x, y, z) = (0, 0, 7) + t(-8, 0, 7) Question 6 (1 point) 3a. A line has slope -3 and y-intercept 5. Find a vector equation of the line. (x, y) = (-3, 5) + t(-3, -3) (x, y) = (0, 5) + t(1, −3) (x, y) = (1,3) + t(0, 5) (x, y) = (5,0)+(0, -3)

Question 5 (1 point) 4c. A line has x-intercept 8 and z-intercept 7. Find a vector equation of the line. (x, y, z) = (-8, 0, 7) + t(8, 0, 0) (x, y, z) = (0, 0, 7) + t(-8, 0, 0) (x, y, z) = (-8, 0, 7) + t(0, 0, 7) (x, y, z) = (0, 0, 7) + t(-8, 0, 7) Question 6 (1 point) 3a. A line has slope -3 and y-intercept 5. Find a vector equation of the line. (x, y) = (-3, 5) + t(-3, -3) (x, y) = (0, 5) + t(1, −3) (x, y) = (1,3) + t(0, 5) (x, y) = (5,0)+(0, -3)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question 5 (1 point) 4c. A line has x-intercept 8 and z-intercept 7. Find a vector equation of the line. (x, y, z) = (-8, 0, 7) + t(8, 0, 0) (x, y, z) = (0, 0, 7) + t(-8, 0, 0) (x, y, z) = (-8, 0, 7) + t(0, 0, 7) (x, y, z) = (0, 0, 7) + t(-8, 0, 7) Question 6 (1 point) 3a. A line has slope -3 and y-intercept 5. Find a vector equation of the line. (x, y) = (-3, 5) + t(-3, -3) (x, y) = (0, 5) + t(1, −3) (x, y) = (1,3) + t(0, 5) (x, y) = (5,0)+(0, -3)
Transcribed Image Text:Question 5 (1 point) 4c. A line has x-intercept 8 and z-intercept 7. Find a vector equation of the line. (x, y, z) = (-8, 0, 7) + t(8, 0, 0) (x, y, z) = (0, 0, 7) + t(-8, 0, 0) (x, y, z) = (-8, 0, 7) + t(0, 0, 7) (x, y, z) = (0, 0, 7) + t(-8, 0, 7) Question 6 (1 point) 3a. A line has slope -3 and y-intercept 5. Find a vector equation of the line. (x, y) = (-3, 5) + t(-3, -3) (x, y) = (0, 5) + t(1, −3) (x, y) = (1,3) + t(0, 5) (x, y) = (5,0)+(0, -3)
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