0Question 45Below are two images showing two different data tables that you wish to link together inTableau. What is the field that forms the basis of the relationship (linkage) between the two datatables in Tableau?Type your answer in the blank/box below, being careful not to make a spelling error when typing inthe field name. Type in the field name EXACTLY as it is shown below.FieldsTypeAbcAbFDFFF.AleAMFieldsTypeAbc000Field NameGolf Club UsedTypeYardsHoleResultBallDate:CourseField NameCourse (Courses.csv)CityStateCountryPhysical TableSheet2Sheet2Sheet2Sheet2Sheet2Sheet2Sheet2Sheet2Remote Field...Golf ClubUsedTypeYardsHoleResultBallDateCoursePhysical Tableirses.csvCourses.csvCourses.csvCourses.csvRemote Field NameCourse (Courses.csv)CityStateCountry

Combining information from different tables into one cohesive whole is made possible by the use of…

Question 45 Below are two images showing two different data tables that you wish to link together in Tableau. What is the field that forms the basis of the relationship (linkage) between the two data tables in Tableau? Type your answer in the blank/box below, being careful not to make a spelling error when typing in the field name. Type in the field name EXACTLY as it is shown below. Fields Type Abc Abc FOFFF Fields Type Abc Field Name - Golf Club Used Type Yards Hole Result Ball Date Course Field Name Course (Courses.csv) City State Country Physical Table Sheet2 Sheet2 Sheet2 Sheet2 Sheet2 Sheet2 Sheet2 Sheet2 Remote Field... GolfClubUsed Type Yards Hole Result Ball Date Course Physical Table Courses.csv Courses.csv Courses.csv Courses.csv Remote Field Name Course (Courses.csv) City State P Country

Question 45 Below are two images showing two different data tables that you wish to link together in Tableau. What is the field that forms the basis of the relationship (linkage) between the two data tables in Tableau? Type your answer in the blank/box below, being careful not to make a spelling error when typing in the field name. Type in the field name EXACTLY as it is shown below. Fields Type Abc Abc FOFFF Fields Type Abc Field Name - Golf Club Used Type Yards Hole Result Ball Date Course Field Name Course (Courses.csv) City State Country Physical Table Sheet2 Sheet2 Sheet2 Sheet2 Sheet2 Sheet2 Sheet2 Sheet2 Remote Field... GolfClubUsed Type Yards Hole Result Ball Date Course Physical Table Courses.csv Courses.csv Courses.csv Courses.csv Remote Field Name Course (Courses.csv) City State P Country

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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SQL DML/DDL There are five tables describing employees of a company, departments, buildings, which department(s) an employee works in (and a percentage of the time for each), and in which building an employee works (an employee may have more than one office). The primary key of each table is the attribute(s) in capitals and underlined. The foreign keys are in italics. Other attributes are not necessarily unique.Employee (EID, Ename, Salary, Start_Date, End_Date)Building (BID, Bname, Address)Department (DID, Dname, Annual_Budget)In_Department (EID, DID, Percentage_Time)In_Building (EID, BID)Write the SQL statements for the following.1. Find the names of Departments where NO employees work. 2. For employees who are still working in the company, end date has no value (empty). For those who have left the company and have end date values, show their names and the duration of their employment in years. 3. Find the names of buildings where more than 50 employees work. 4. The tables have…
SQL: Dog DataIn each question below, you will define a new table based on the following tables.CREATE TABLE parents ASSELECT "abraham" AS parent, "barack" AS child UNIONSELECT "abraham" , "clinton" UNIONSELECT "delano" , "herbert" UNIONSELECT "fillmore" , "abraham" UNIONSELECT "fillmore" , "delano" UNIONSELECT "fillmore" , "grover" UNIONSELECT "eisenhower" , "fillmore";CREATE TABLE dogs ASSELECT "abraham" AS name, "long" AS fur, 26 AS height UNIONSELECT "barack" , "short" , 52 UNIONSELECT "clinton" , "long" , 47 UNIONSELECT "delano" , "long" , 46 UNIONSELECT "eisenhower" , "short" , 35 UNIONSELECT "fillmore" , "curly" , 32 UNIONSELECT "grover" , "short" , 28 UNIONSELECT "herbert" , "curly" , 31;CREATE TABLE sizes ASSELECT "toy" AS size, 24 AS min, 28 AS max UNIONSELECT "mini" , 28 , 35 UNIONSELECT "medium" , 35 , 45 UNIONSELECT "standard" , 45 , 60;Q1: Size of DogsThe Fédération Cynologique Internationale classifies a standard poodle as over 45 cm and up to 60 cm.The sizes table…
The Horse table has the following columns: ID - integer, auto increment, primary key RegisteredName - variable-length string Breed - variable-length string, must be one of the following: Egyptian Arab, Holsteiner, Quarter Horse, Paint, Saddlebred Height - decimal number, must be between 10.0 and 20.0 BirthDate - date, must be on or after Jan 1, 2015 Insert the following data into the Horse table: RegisteredName Breed Height BirthDate Babe Quarter Horse 15.3 2015-02-10 Independence Holsteiner 16.0 2017-03-13 Ellie Saddlebred 15.0 2016-12-22 NULL Egyptian Arab 14.9 2019-10-12
Task 2: The Car Maintenance team also wants to store the actual maintenance operations in the database. The team wants to start with a table to store CAR_ID (CHAR(5)), MAINTENANCE_TYPE_ID (CHAR(5)) and MAINTENANCE_DUE (DATE) date for the operation. Create a new table named MAINTENANCES. The PRIMARY_KEY should be the combination of the three fields. The CAR_ID and MAINTENANCE_TYPE_ID should be foreign keys to their original tables. Cascade update and cascade delete the foreign keys. Create a new table to store maintenance operations Test Query DESCRIBE MAINTENANCES Expected Results Field Type Null Key Default Extra CAR_ID char(5) NO PRI NULL MAINTENANCE_TYPE_ID char(5) NO PRI NULL MAINTENANCE_DUE date NO PRI NULL
Task 2: The Car Maintenance team also wants to store the actual maintenance operations in the database. The team wants to start with a table to store CAR_ID (CHAR(5)), MAINTENANCE_TYPE_ID (CHAR(5)) and MAINTENANCE_DUE (DATE) date for the operation. Create a new table named MAINTENANCES. The PRIMARY_KEY should be the combination of the three fields. The CAR_ID and MAINTENACNE_TYPE_ID should be foreign keys to their original tables. Cascade update and cascade delete the foreign keys. Answer in MYSQL please
MySQL CREATE TABLE students ( id INT PRIMARY KEY, first_name VARCHAR(50), last_name VARCHAR(50), age INT, major VARCHAR(50), faculty VARCHAR(50)); CREATE TABLE location ( id INT PRIMARY KEY, name VARCHAR(50), rooms INT); CREATE TABLE faculty ( id INT PRIMARY KEY, name VARCHAR(50), department_id INT); 4. Find the number of employees in each department who get no commission or have salary less than5000.5. Find the maximum salary of employees in each department that the employee was hired 15 yearsbefore now. *hint: user TIMESTAMPDIFF(<unit type>,<Date_value 1>,<Date_value 2>), the unitcan be YEAR, MONTH, DAY, HOUR, etc...6. Find the last name of all employees that were not hired on Tuesday *hint: (UseDATE_FORMAT() function amd the format you need is %W, also use UPPER()7. Find the number of employees in each department who have a manager.8. Find the number of employees for each manager whose employees' minimum salary is greaterthan 5000.9. Find the number of…
Go to the w3schools website’s SQL browser IDE. This is where you canwrite and test your SQL code using their databases. Once you are happywith it, paste your code in a text file named Student.txt and save it in yourtask folder.● Write the SQL code to create a table called Student. The table structure issummarised in the table below (Note that STU_NUM is the primary key):Attribute Name Data TypeSTU_NUM CHAR(6)STU_SNAME VARCHAR(15)STU_FNAME VARCHAR(15)STU_INITIAL CHAR(1)STU_STARTDATE DATECOURSE_CODE CHAR(3)PROJ_NUM INT(2)● After you have created the table in question 1, write the SQL code to enterthe first two rows of the table as below:STU_NUMSTU_SNAMESTU_FNAMESTU_INITIALSTU_STARTDATECOURSE_CODEPROJ_NUM01 Snow John E 05-Apr-14 201 602 Stark Arya C 12-Jul-17 305 11● Assuming all the data in the Student table has been entered as shownbelow, write the SQL code that will list all attributes for a COURSE_CODE of305.…
Explain how users may protect themselves against Session Hijacking attacks. Discuss possible defenses to these assaults.
WEEK 9 ASSIGNMENT#3 Part I: Complete the following exercise: Create the following table with the correct columns. Call your new table: student_course (see below). Populate this table with four rows. Make sure the student id column contains values that are also in the student id column of your student table. student id course id semester year Join the student and student_course table where the student id values are the same. Join the student and student_course table where the student id values are the same and year is equal to 2020. Create a select statement that will return the length of the last name column by joining the student and student_course table where the student id values are the same and enroll month is June. Once you have completed your assignment, copy and paste the script into a Word document. Part II: Complete the following exercise: Using a subquery, select student first name where the student is in the student course table. Using a subquery, select the…
Assume the EMPLOYEE table contains four attributes, ID, DEPT, SALARY and NAME, and has the following rows ID DEPT SALARY NAME 100 SALES 40000 Smith 101 RD 38000 Terry 102 HR 60000 David 103 SALES 58000 Ellie 104 RD 70000 Judy The DEPARTMENT table contains two attributes, DEPTNAME and PHONE, and has the following rows: DEPTNAME PHONE RD 8596001234 SALES 8596005555 HR 8596009876 A.) The EMPLOYEE table needs to enforce the following integrity constraints: • The ID is the primary key. • The DEPT column is a foreign key that references the DEPTNAME in the DEPARTMENT table, so that any value that appears in the DEPT column should also exist in the DEPARTMENT table. • The value for the NAME column can never be null. What should be the statement used to create the EMPLOYEE table, if 1) the table was created as a partitioned table such…