Question 4 of 32 How many moles of aluminum are required to completely react with 107 mL of 6.00 M H2SO4 according to the balanced chemical reaction: 2 Al(s) + 3 H2SO (aq) –→ Al2(SO,)3(aq) + 3 H2(g) 1 LH2SO4 6.00 107 STARTING AMOUNT 1000 mlHSO, 1LH2SO4 6.00 107 mL H2SO4 x 1000 mL H2S04 1 98.08 1000 2 6.022 x 1023 6.00 0.963 1 3 428 107 0.001 0.428 0.0374 mol Al2(SO4)3 L H2SO4 M H2SO, g Al2(SO4)3 mol H2 mL H2SO, mol H2SO, g H2SO4 mol Al gAl g H2 cheag .com

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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How
many
moles of aluminum
are
required
to
completely
react
with
107
mL
of
6.00
M H₂SO₄
according
to
the
balanced
chemical
reaction:
 
 
2
Al(s)
+
3
H₂SO₄(aq)
Al₂(SO₄)₃(aq)
+
3
H₂(g)
Question 4 of 32
How many moles of aluminum are required to completely react with 107
mL of
6.00 M H2SO4 according to the balanced chemical reaction:
2 Al(s) + 3 H2SO4(aq) → Al2(SO4)3(aq) +
3 H2(g)
1
LH2SO4
6.00
107
STARTING AMOUNT
1000
1
1L H2SO4
6.00
107 mL H2SO4 x
1000 mL H2S04
1
%D
98.08
1000
6.022 x 1023
6.00
0.963
1
3
428
107
0.001
0.428
0.0374
mol Al2(SO4)3
L H2SO4
M H2SO4 g Alz(SO4)3
mol H2
mL H2SO4
mol H2SO4
g H2SO4
mol Al
Al
g H2
echeaa com
MacBook Pro
2.
Transcribed Image Text:Question 4 of 32 How many moles of aluminum are required to completely react with 107 mL of 6.00 M H2SO4 according to the balanced chemical reaction: 2 Al(s) + 3 H2SO4(aq) → Al2(SO4)3(aq) + 3 H2(g) 1 LH2SO4 6.00 107 STARTING AMOUNT 1000 1 1L H2SO4 6.00 107 mL H2SO4 x 1000 mL H2S04 1 %D 98.08 1000 6.022 x 1023 6.00 0.963 1 3 428 107 0.001 0.428 0.0374 mol Al2(SO4)3 L H2SO4 M H2SO4 g Alz(SO4)3 mol H2 mL H2SO4 mol H2SO4 g H2SO4 mol Al Al g H2 echeaa com MacBook Pro 2.
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