Question 4 If u and v are vector valued functions of the variable t, and u(2) = (−1.2168, 1.0203, −0.9872) v(2) = (−1.0302, 1.3038, −1.9027) u′(2) = (1, −1, 0) v'(2) = (1,0, −1) d then the value, at t = 2, of - (cos(u · v)) is . dt 5.5127 -3.4574 -4.2981 -6.8913 O7.5457 0.9701 -2.5970 -2.4838 1 pts

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