Question 4 Given one-dimensional Heat equation as shown below "ng = 'n u(0,t) = u(27,1) = 0, %3! %3D t>0 u(x,0) = 2 sin (2x), 00 is an eigenvalue for X' +kX = 0. c) Show that the series solution of the Heat equation is u(x,1)=Eb.e d) Based on your understanding, what will happen to X(x), if k = -10?

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Question 4
Question 4
Given one-dimensional Heat equation as shown below
u, = 6u.
u(0,t) = u(27,1) = 0,
t>0
u(x,0) = 2 sin (2x),
0<x< 27
which lead to two ordinary differential equations X"+kX =0 and T"+6kT = 0.
a) Find the general solution for T'+6kT = 0.
b) Show that for the case k=r',r>0 is an eigenvalue for X"+kX = 0.
nx
c) Show that the series solution of the Heat equation is u(x,t)3Db,e:
sin
d) Based on your understanding, what will happen to X(x), if k = -10?
Transcribed Image Text:Question 4 Question 4 Given one-dimensional Heat equation as shown below u, = 6u. u(0,t) = u(27,1) = 0, t>0 u(x,0) = 2 sin (2x), 0<x< 27 which lead to two ordinary differential equations X"+kX =0 and T"+6kT = 0. a) Find the general solution for T'+6kT = 0. b) Show that for the case k=r',r>0 is an eigenvalue for X"+kX = 0. nx c) Show that the series solution of the Heat equation is u(x,t)3Db,e: sin d) Based on your understanding, what will happen to X(x), if k = -10?
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