Homework Help is Here – Start Your Trial Now!
Engineering
Computer Engineering
Question 4 Given below a Point-to-point communication trace taken by Wireshark a network protocol analyzer software. ETHER: Ethernet Header ETHER: Packet 3 arrived at 11:42:27.64 ETHER: Packet size = 64 bytes ETHER: Destination = 8:0:20:18:ba:40 ETHER: Source = aa:0:4:0:lf:c8 ETHER: Ethertype = 0800 (IP) IP: IP Header IP: Version = 4 IP: Header length = 20 bytes IP: Type of service = 0x00 IP: х хх. IP: ...0 IP: IP: IP: Total length = 40 bytes .... = 0 (precedence) = normal delay 0... = normal throughput .0.. = normal reliability IP: Identification = 41980 IP: Flags = 0x4 IP: .1.. = do not fragment = last fragment IP: ..0. IP: Fragment offset = 0 bytes IP: Time to live = 63 seconds/hops IP: Protocol = 6 IP: Header checksum = af63 IP: Source address = 163.173.32.65 IP: Destination address = 216.58.207.4 IP: No options TCP: ТСР Неader TCP: Source port = 1368 TCP: Destination port = 25 (SMTP) TCP: Sequence number = 143515262 TCP: Acknowledgement number = 3128387273 TCP: Data offset = 20 bytes TCP: Flags = 0x10 TCP: ..0. TCP: TCP: TCP: = No urgent pointer = Acknowledgement ..1 ... 0... = No push .0.. = No reset ..0. = No Syn .0 = No Fin TCP: Window = 32120 ТСР: TCP: TCP: Checksum = 0x3c30 TCP: Urgent pointer = 0 TCP: No options Analyse the above trace and indicate the following: a) The protocol used in each of the following layers: Data Link, Network, Transport and Application. b) Source and destination MAC addresses c) Source and destination IP addresses. d) Explain the value 0x10 shown in the flags field (highlighted in blue color in the trace) by indication the type of this captured message? e) Explain the meaning of the value shown in window size (highlighted in blue color in the

Question 4 Given below a Point-to-point communication trace taken by Wireshark a network protocol analyzer software. ETHER: Ethernet Header ETHER: Packet 3 arrived at 11:42:27.64 ETHER: Packet size = 64 bytes ETHER: Destination = 8:0:20:18:ba:40 ETHER: Source = aa:0:4:0:lf:c8 ETHER: Ethertype = 0800 (IP) IP: IP Header IP: Version = 4 IP: Header length = 20 bytes IP: Type of service = 0x00 IP: х хх. IP: ...0 IP: IP: IP: Total length = 40 bytes .... = 0 (precedence) = normal delay 0... = normal throughput .0.. = normal reliability IP: Identification = 41980 IP: Flags = 0x4 IP: .1.. = do not fragment = last fragment IP: ..0. IP: Fragment offset = 0 bytes IP: Time to live = 63 seconds/hops IP: Protocol = 6 IP: Header checksum = af63 IP: Source address = 163.173.32.65 IP: Destination address = 216.58.207.4 IP: No options TCP: ТСР Неader TCP: Source port = 1368 TCP: Destination port = 25 (SMTP) TCP: Sequence number = 143515262 TCP: Acknowledgement number = 3128387273 TCP: Data offset = 20 bytes TCP: Flags = 0x10 TCP: ..0. TCP: TCP: TCP: = No urgent pointer = Acknowledgement ..1 ... 0... = No push .0.. = No reset ..0. = No Syn .0 = No Fin TCP: Window = 32120 ТСР: TCP: TCP: Checksum = 0x3c30 TCP: Urgent pointer = 0 TCP: No options Analyse the above trace and indicate the following: a) The protocol used in each of the following layers: Data Link, Network, Transport and Application. b) Source and destination MAC addresses c) Source and destination IP addresses. d) Explain the value 0x10 shown in the flags field (highlighted in blue color in the trace) by indication the type of this captured message? e) Explain the meaning of the value shown in window size (highlighted in blue color in the

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
See similar textbooks
icon
Related questions
Question
Question 4 Given below a Point-to-point communication trace taken by Wireshark a network protocol analyzer software. ETHER: Ethernet Header ETHER: Packet 3 arrived at 11:42:27.64 ETHER: Packet size = 64 bytes ETHER: Destination = 8:0:20:18:ba:40 ETHER: Source = aa:0:4:0:1f:c8 ETHER: Ethertype = 0800 (IP) IP: IP Header IP: Version = 4 = 20 bytes IP: Header length IP: Type of service = 0x00 = 0 (precedence) = normal delay 0... = normal throughput = normal reliability IP: х хх. ... IP: ... 0 .... IP: IP: .0.. IP: Total length = 40 bytes = 41980 IP: Identification IP: Flags = 0x4 = do not fragment last fragment 0 bytes IP: .1.. IP: ..0. IP: Fragment offset = IP: Time to live = 63 seconds/hops IP: Protocol = 6 IP: Header checksum = af63 IP: Source address = 163.173.32.65 IP: Destination address = 216.58.207.4 IP: No options ТСP: ----- ТСР Нeader TCP: Source port = 1368 TCP: Destination port = 25 (SMTP) TCP: Sequence number = 143515262 TCP: Acknowledgement number = 3128387273 TCP: Data offset = 20 bytes TCP: Flags = 0x10 ТCР: ..0. ТCР: ...1 = No urgent pointer = Acknowledgement = No push TCP: 0... TCP: .0.. = No reset ТСP: ..0. = No Syn TCP: ...0 = No Fin TCP: Window = 32120 TCP: Checksum = 0x3c30 TCP: Urgent pointer = 0 TCP: No options Analyse the above trace and indicate the following: a) The protocol used in each of the following layers: Data Link, Network, Transport and Application. b) Source and destination MAC addresses c) Source and destination IP addresses. d) Explain the value 0x10 shown in the flags field (highlighted in blue color in the trace) by indication the type of this captured message? e) Explain the meaning of the value shown in window size (highlighted in blue color in the trace)?
Transcribed Image Text:Question 4 Given below a Point-to-point communication trace taken by Wireshark a network protocol analyzer software. ETHER: Ethernet Header ETHER: Packet 3 arrived at 11:42:27.64 ETHER: Packet size = 64 bytes ETHER: Destination = 8:0:20:18:ba:40 ETHER: Source = aa:0:4:0:1f:c8 ETHER: Ethertype = 0800 (IP) IP: IP Header IP: Version = 4 = 20 bytes IP: Header length IP: Type of service = 0x00 = 0 (precedence) = normal delay 0... = normal throughput = normal reliability IP: х хх. ... IP: ... 0 .... IP: IP: .0.. IP: Total length = 40 bytes = 41980 IP: Identification IP: Flags = 0x4 = do not fragment last fragment 0 bytes IP: .1.. IP: ..0. IP: Fragment offset = IP: Time to live = 63 seconds/hops IP: Protocol = 6 IP: Header checksum = af63 IP: Source address = 163.173.32.65 IP: Destination address = 216.58.207.4 IP: No options ТСP: ----- ТСР Нeader TCP: Source port = 1368 TCP: Destination port = 25 (SMTP) TCP: Sequence number = 143515262 TCP: Acknowledgement number = 3128387273 TCP: Data offset = 20 bytes TCP: Flags = 0x10 ТCР: ..0. ТCР: ...1 = No urgent pointer = Acknowledgement = No push TCP: 0... TCP: .0.. = No reset ТСP: ..0. = No Syn TCP: ...0 = No Fin TCP: Window = 32120 TCP: Checksum = 0x3c30 TCP: Urgent pointer = 0 TCP: No options Analyse the above trace and indicate the following: a) The protocol used in each of the following layers: Data Link, Network, Transport and Application. b) Source and destination MAC addresses c) Source and destination IP addresses. d) Explain the value 0x10 shown in the flags field (highlighted in blue color in the trace) by indication the type of this captured message? e) Explain the meaning of the value shown in window size (highlighted in blue color in the trace)?
Expert Solution
steps

Step by step

Solved in 3 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Computer Networking: A Top-Down Approach (7th Edi…
Computer Networking: A Top-Down Approach (7th Edi…
Computer Engineering
ISBN:
9780133594140
Author:
James Kurose, Keith Ross
Publisher:
PEARSON
Computer Organization and Design MIPS Edition, Fi…
Computer Organization and Design MIPS Edition, Fi…
Computer Engineering
ISBN:
9780124077263
Author:
David A. Patterson, John L. Hennessy
Publisher:
Elsevier Science
Network+ Guide to Networks (MindTap Course List)
Network+ Guide to Networks (MindTap Course List)
Computer Engineering
ISBN:
9781337569330
Author:
Jill West, Tamara Dean, Jean Andrews
Publisher:
Cengage Learning
Concepts of Database Management
Concepts of Database Management
Computer Engineering
ISBN:
9781337093422
Author:
Joy L. Starks, Philip J. Pratt, Mary Z. Last
Publisher:
Cengage Learning
Prelude to Programming
Prelude to Programming
Computer Engineering
ISBN:
9780133750423
Author:
VENIT, Stewart
Publisher:
Pearson Education
Sc Business Data Communications and Networking, T…
Sc Business Data Communications and Networking, T…
Computer Engineering
ISBN:
9781119368830
Author:
FITZGERALD
Publisher:
WILEY
SEE MORE TEXTBOOKS