I need the answer as soon as possible Question 4Draw the free-body diagram, and select the correct equilibrium moment equation about A.A). EMA = 0 = NB cos 30° (11) - NB sin 30°(6) – 1006 in- S in50 IbDAB). EMA = 0 = NB sin 30°(11) + NB Cos 30°(6) – 1003 in100 in-lbC). EMA = 0 = NB cos 30°(11)+ NB sin 30°(6)3 inD). EMA = 0 = NB cos 30°(11) + NB sin 30° (6) - 10030E). E MA = 0 = Ng sin 30°(11) + Ng cos 30°(6)

Answered: Image /qna-images/answer/23c72b7e-d083-4eff-9c88-c0f5c3a26b93.jpg

Question 4 Draw the free-body diagram, and select the correct equilibrium moment equation about A. A). EMA = 0 = NB cos 30°(11) – NB sin 30°(6) – 100 -6 in- - 5 in 50 Ib B). EMA = 0 = NB sin 30°(11) + NB cos 30°(6) – 100 3 in 100 in-lb C). EMA = 0 = NB cos 30°(11) + NB sin 30°(6) 3 in D). EMA = 0 =NB cos 30°(11) + NB sin 30°(6) – 100 30 E). EMA = 0 = NB sin 30°(11) + NB cos 30° (6)

Question 4 Draw the free-body diagram, and select the correct equilibrium moment equation about A. A). EMA = 0 = NB cos 30°(11) – NB sin 30°(6) – 100 -6 in- - 5 in 50 Ib B). EMA = 0 = NB sin 30°(11) + NB cos 30°(6) – 100 3 in 100 in-lb C). EMA = 0 = NB cos 30°(11) + NB sin 30°(6) 3 in D). EMA = 0 =NB cos 30°(11) + NB sin 30°(6) – 100 30 E). EMA = 0 = NB sin 30°(11) + NB cos 30° (6)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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