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Question 4 A single-stage absorber is used to contact a gas mixture at 1 atm with recycled water solvent at 298 K. The gas mixture inlet contains air and acetone, with a molar fraction of acetone of y/2 = 0.11. Meanwhile, the recycled solvent inlet contains water and acetone, with a molar fraction of acetone of x0=0.002. The total inlet gas flow and total inlet liquid flow are 30 kmol/h and 100 kmol/h, respectively. The two exit gas and liquid streams reach equilibrium. Assume that water does not vaporize to gas. a) By using the material balance on acetone (A), show that the compositions of acetone at the two outlet phases, x. and y, can be expressed by the following relationship 28.5144 +7.629=1 b) If the composition of acetone at the liquid outlet, x is 0.017, calculate the amounts and compositions of the two outlet phases c) Predict the Henry's law constant for acetone in water at 298 K.

Question 4 A single-stage absorber is used to contact a gas mixture at 1 atm with recycled water solvent at 298 K. The gas mixture inlet contains air and acetone, with a molar fraction of acetone of y/2 = 0.11. Meanwhile, the recycled solvent inlet contains water and acetone, with a molar fraction of acetone of x0=0.002. The total inlet gas flow and total inlet liquid flow are 30 kmol/h and 100 kmol/h, respectively. The two exit gas and liquid streams reach equilibrium. Assume that water does not vaporize to gas. a) By using the material balance on acetone (A), show that the compositions of acetone at the two outlet phases, x. and y, can be expressed by the following relationship 28.5144 +7.629=1 b) If the composition of acetone at the liquid outlet, x is 0.017, calculate the amounts and compositions of the two outlet phases c) Predict the Henry's law constant for acetone in water at 298 K.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question 4 A single-stage absorber is used to contact a gas mixture at 1 atm with recycled water solvent at 298 K. The gas mixture inlet contains air and acetone, with a molar fraction of acetone of y2 = 0.11. Meanwhile, the recycled solvent inlet contains water and acetone, with a molar fraction of acetone of x0= 0.002. The total inlet gas flow and total inlet liquid flow are 30 kmol/h and 100 kmol/h, respectively. The two exit gas and liquid streams reach equilibrium. Assume that water does not vaporize to gas. a) By using the material balance on acetone (A), show that the compositions of acetone at the two outlet phases, x and y, can be expressed by the following relationship +) + 7.629 ( 1 X 14 ) YA 28.514 x₁ = 1 b) If the composition of acetone at the liquid outlet, x is 0.017, calculate the amounts and compositions of the two outlet phases c) Predict the Henry's law constant for acetone in water at 298 K.,
Transcribed Image Text:Question 4 A single-stage absorber is used to contact a gas mixture at 1 atm with recycled water solvent at 298 K. The gas mixture inlet contains air and acetone, with a molar fraction of acetone of y2 = 0.11. Meanwhile, the recycled solvent inlet contains water and acetone, with a molar fraction of acetone of x0= 0.002. The total inlet gas flow and total inlet liquid flow are 30 kmol/h and 100 kmol/h, respectively. The two exit gas and liquid streams reach equilibrium. Assume that water does not vaporize to gas. a) By using the material balance on acetone (A), show that the compositions of acetone at the two outlet phases, x and y, can be expressed by the following relationship +) + 7.629 ( 1 X 14 ) YA 28.514 x₁ = 1 b) If the composition of acetone at the liquid outlet, x is 0.017, calculate the amounts and compositions of the two outlet phases c) Predict the Henry's law constant for acetone in water at 298 K.,
Appendix I Heat Transfer Heat transfer by conduction Q= Hollow cylinder: Q= KA(T-T₂) T₁-T₂ Ar R Hollow sphere: Q=- 1= Drying of Solids Constant Rate Drying Period t= L (X₁-X.) AR a= 2.nd.k(T.-T.) In Falling Rate Drying Period (through origin) LXX AR X₂ 4rk (T-T₂) 1 (9) 1 1/2 R-R X-X₂ 1 Falling Rate Drying Period (does not through origin) 1= LhR aA R₂ Absorption Henry's Law H' = H/P Material Balance on Solute (A) X10 ¹( ²0 )+v[2® )=L( ²0 )+r(2) 40
Transcribed Image Text:Appendix I Heat Transfer Heat transfer by conduction Q= Hollow cylinder: Q= KA(T-T₂) T₁-T₂ Ar R Hollow sphere: Q=- 1= Drying of Solids Constant Rate Drying Period t= L (X₁-X.) AR a= 2.nd.k(T.-T.) In Falling Rate Drying Period (through origin) LXX AR X₂ 4rk (T-T₂) 1 (9) 1 1/2 R-R X-X₂ 1 Falling Rate Drying Period (does not through origin) 1= LhR aA R₂ Absorption Henry's Law H' = H/P Material Balance on Solute (A) X10 ¹( ²0 )+v[2® )=L( ²0 )+r(2) 40
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