Question 4 (1 point) 5b. Write the scalar equation equivalent of the line with normal vector n = [0, -5] and passing through the point (4, 1). Oy-1=0 4x+y+1=0 Oy+1=0 O-5y+1=0

find the vector equation for the line through the point A = (5, -2, 1) at t = 0. and B = (-3, 1, -2) at t = 1.

Write the scalar equation of the line given the normal vector n = 3, point Po(-2,-4). and a

Give a vector parametric equation for the line through the point (4,-3) that is perpendicular to the line <1−4t,3t−3>

Write the scalar equation of the line given the normal vector n =[1,−1] and a point Po (-5,1)

Develop vector and parametric equations for the line through (7,2,-1) and parallel to r = (4,7,0) + s(4,-5,1). Please answer  Thank you.

Let L. be the line with parametric equations x=-9-t y=-8-31 ==-1+2t Find the vector equation for a line that passes through the point P-(-6, -8,-6) and intersects L at a point that is distance 4 from the point Q- (-9,-8,-1). Note that there are two possible correct answers. Use the square root symbol where needed to give an exact value for your answor 000 000 0+10 lat je

Parametrize the line of intersection between 3x + 6y-z = 4 and -2x + 2y - z = 1.