Question 3 V = - E dr Two, hollow, spherical conductors, are placed concentrically in free space. The inner sphere has radius R; and the outer Ro. The inner sphere has a charge Q, the outer sphere has a charge -Q, see Figure 3. in this case, to calculate the voltage between the two spheres. Hence show that the capacitance between the spheres is R. C = (c) If the radii are R; = 1 cm and R, = 1.1 cm determine the capacitance. E [20 marks] Figure 3 (a) Use Gauss's law to show that, between the two spheres, the electric field is E = 4n€,r² (1) and zero everywhere else. State all assumptions that you make. Hint: you should set the Gaussian surface to be the surface of a sphere of radius r, sharing the same centre as the charged spheres. Remember that if the flux density is perpendicular to the Gaussian surface and constant over its surface then Gauss' law reduces to D dA = DA = Q where A is the Gaussian surface's area. (b) Use the result in equation (1) and the definition of potential difference,

Introductory Circuit Analysis (13th Edition)
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Question 3
Ri
V = -
E dr
Two, hollow, spherical conductors, are placed concentrically in free space. The inner sphere
has radius R; and the outer Ro. The inner sphere has a charge Q, the outer sphere has a
charge -Q, see Figure 3.
Ro
in this case, to calculate the voltage between the two spheres. Hence show that the
capacitance between the spheres is
-0
4πε,
C3=
(c) If the radii are R; = 1 cm and R, = 1.1 cm determine the capacitance.
E
E
[20 marks]
Figure 3
(a) Use Gauss's law to show that, between the two spheres, the electric field is
E =
4TE,rz
(1)
and zero everywhere else. State all assumptions that you make.
Hint: you should set the Gaussian surface to be the surface of a sphere of radius r,
sharing the same centre as the charged spheres. Remember that if the flux density is
perpendicular to the Gaussian surface and constant over its surface then Gauss' law
reduces to
D dA = DA = Q
where A is the Gaussian surface's area.
(b) Use the result in equation (1) and the definition of potential difference,
Transcribed Image Text:Question 3 Ri V = - E dr Two, hollow, spherical conductors, are placed concentrically in free space. The inner sphere has radius R; and the outer Ro. The inner sphere has a charge Q, the outer sphere has a charge -Q, see Figure 3. Ro in this case, to calculate the voltage between the two spheres. Hence show that the capacitance between the spheres is -0 4πε, C3= (c) If the radii are R; = 1 cm and R, = 1.1 cm determine the capacitance. E E [20 marks] Figure 3 (a) Use Gauss's law to show that, between the two spheres, the electric field is E = 4TE,rz (1) and zero everywhere else. State all assumptions that you make. Hint: you should set the Gaussian surface to be the surface of a sphere of radius r, sharing the same centre as the charged spheres. Remember that if the flux density is perpendicular to the Gaussian surface and constant over its surface then Gauss' law reduces to D dA = DA = Q where A is the Gaussian surface's area. (b) Use the result in equation (1) and the definition of potential difference,
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