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QUESTION 3 In a baseball field, the four bases are at the vertices of a square 90 ft on a side. The pitching rubber is 60.5 ft from the home plate. How far is it from the pitching rubber to the first base? Fig. 9.71 90.0 ft Copyright 2015 Pearson Canada Inc. Distance = 58.7 ft Distance = 63.7 ft Distance = 72.7 ft Distance = 53.7 ft 60.5 ft

QUESTION 3 In a baseball field, the four bases are at the vertices of a square 90 ft on a side. The pitching rubber is 60.5 ft from the home plate. How far is it from the pitching rubber to the first base? Fig. 9.71 90.0 ft Copyright 2015 Pearson Canada Inc. Distance = 58.7 ft Distance = 63.7 ft Distance = 72.7 ft Distance = 53.7 ft 60.5 ft

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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QUESTION 3 In a baseball field, the four bases are at the vertices of a square 90 ft on a side. The pitching rubber is 60.5 ft from the home plate. How far is it from the pitching rubber to the first base? Fig. 9.71 90.0 ft Copyright 2015 Pearson Canada Inc. Distance = 58.7 ft %3D Distance = 63.7 ft Distance = 72.7 ft Distance = 53.7 ft 60.5 ft
Transcribed Image Text:QUESTION 3 In a baseball field, the four bases are at the vertices of a square 90 ft on a side. The pitching rubber is 60.5 ft from the home plate. How far is it from the pitching rubber to the first base? Fig. 9.71 90.0 ft Copyright 2015 Pearson Canada Inc. Distance = 58.7 ft %3D Distance = 63.7 ft Distance = 72.7 ft Distance = 53.7 ft 60.5 ft
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