QUESTION 3If you rejected Ho at the 0.10 level of significance, thenO you may reject it at the 0.05 levelO you must reject it at the 0.01 levelO you will not reject it at the 0.05 levelO you will not reject it at the 0.01 levelQUESTION 4A retail store wants to start a delivery service, which will not be financially effective unless the average order is 450 AED. They conducted a test, with5% significance level, and the resultant p-value was 0.045. If the true average of the bill is 450 AED, which of the following describes the test?O They committed Type I errorO They need more informationO They committed Type Il errorOThey took a correct decisionQUESTION 5An online website for selling used cars reported that the mean price of a three-year-old sports vehicle (in good condition) is less than 100,000AED. You wanted to test this claim and selected a random sample of 200 similar vehicles and found their mean price is 108,000 AED and astandard deviation of 4500 AED. Which test would be appropriate for this test?O Neither one-sample z-test nor one-sample t-testO One-sample z-testO One-sample t-testO Either one-sample z-test or one-sample t-test

Method: Reject H0 , if P-value is less than the level of significance.

Answered: QUESTION 3 If you rejected Ho at the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Which of the following is NOT true about what a t test does? It assess the causality between two numeric values. It is used when the IV is nominal and DV is continuous. It compares two groups' means. It can be used with single-sample or between-subject designs.
16% of all Americans suffer from sleep apnea. A researcher suspects that a different percentage of those who live in the inner city have sleep apnea. Of the 337 people from the inner city surveyed, 47 of them suffered from sleep apnea. What can be concluded at the level of significance of α= 0.05? a. The test statistic= (please show your answer to 3 decimal places.) b. The p-value = (Please show your answer to 4 decimal places.)
In a test of hypothesis, the null hypothesis is that the population mean is equal to 24 and the alternative hypothesis is that the population mean is not equal to 24. The test is to be made at the 5% significance level. The critical values of z are: a. –2.07 and 2.07 b. –1.65 and 1.65 c. –1.96 and 1.96 d. –2.17 and 2.17
A new screening test for Lyme disease is developed for use in the general population. The sensitivity and specificity of the new test are 60% and 70%, respectively. Five hundred people are screened at a clinic during the first year the new test is implemented. Assume the true prevalence of Lyme disease among clinic attendees is 10%. Calculate the predictive value of a positive test.
The Youth Risk Behavior Survey (a study of public high school students) showed that 45 of 675 girls and 103 of 621 boys had been in a physical fight on school property one or more times during the past 12 months Using 5% significance, perform an appropriate test of hypothesis that the proportion of girlsinvolved in a physical fight on school property is less than the proportion of boys involved in a physical fight on school property.Step 1: H0: ________________ Ha: ____________________ Significance level α =0.05Step 2: Check necessary data conditions and compute an appropriate test statistic:Step 3: Compute corresponding p-value
QUESTION 23 It was found that in a study of air-bag effectiveness 900 crashes of midsize cars equipped with air bags, 70 of the crashes resulted in hospitalization of the drivers. We want to test the claim that the air-bag hospitalization rate is more that the 6.8% rate for crashes of midsize cars equipped with automatic safetly belts. At 0.05 significance level we conclude that Othere is sufficient evidence to support the claim that for crashes of midsize cars, the air-bag hospitalization rate exeeds the 6.8% rate for automatic safetly belts. there is no sufficient evidence to support the claim that for crashes of midsize cars, the air-bag hospitalization rate exceeds the 6.8% rate for automatic safetly belts. Othere is sufficient evidence to support the claim that for crashes of midsize cars, the air-bag hospitalization rate is at least 6.8% rate for automatic safetly belts. there is no sufficient evidence to support the claim that for crashes of midsize cars, the air-bag…
S-adenosyl methionine (SAM-e) is a naturally occurring compound in human cells that is thought to have an effect on depression symptoms. Suppose that a researcher is interested in testing SAM-e on patients who are struggling with cancer. She obtains a sample of n = 20 patients and asks each person to take the suggested dosage each day for 4 weeks. At the end of the 4-week period, each individual takes the Beck Depression Inventory (BDI), which is a 21-item, multiple-choice self-report inventory for measuring the severity of depression. The scores from the sample produced a mean of M = 24.4 with a standard deviation of s = 6.02. In the general population of cancer patients, the standardized test is known to have a population mean of 27.2. Because there are no previous studies using SAM-e with this population, the researcher doesn't know how it will affect these patients; therefore, she uses a two-tailed single-sample t test to test the hypothesis. From the following, select the correct…
what is 1. P value 2. Z value 3. Critical value 4. Reject or do not reject 5. State conclusion
What is the critical value? A. 2.33 B. 2.492 C. 2.575 D. 2.797
Consider the scenario ai from the previous question. Suppose you take an SRS of 50 avocados and find that the mean is 1.1 inches, which yields a p-value of 0.0542. What conclusion would you draw at the =0.05 level? At the =0.10level?
Suppose a researcher surveyed the general public in two countries, asking the question "Do you think that we already started observing the negative impacts of global warming?". The below table summarizes the answers. Test at 5% significance level that the share of "significantly" answer is statistically significantly different in these countries. Enter your answer as the critical value calculated, with 2 digits after the decimal point after rounding the 3rd digit (e.g. 2.34567 = 2.35). Country A Country B Significantly 40 40 Neutral 50 30 Insignificantly 70 10

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