QUESTION 3 If a random sample of size 15 is drawn from a normally distributed population with mean 23 minutes. What is the probability that the sample mean exceeds 25.905 minutes, if the sample standard deviation is 6.39 minutes? O 0.95 0.0392 O 0.9608 0.05

Q: 2(3y-5)=34

A: We will see the ans in next step

Q: w + 4 w + 10 6. 8.

A:

Q: -4(7j+2)=10

A: Given expression,

Q: State the appropriate hypotheses. O Họi Hz # H2 # H3 * H4 Hạ: all four u's are equal byi - Eri = Zri…

A: Given Data :   Box-Type 1 Box-Type 2 Box-Type 3 Box-Type 4   655.5 789.2 737.1 646.1   788.3…

Q: × if と-11616 tai g 2. Q3/hnd

A: To find x if x=16+16tan2θ. Solution: We have identity, sec2θ-tan2θ=1 So, sec2θ=1+tan2θ Solving the…

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A: Let us consider that                     A=abcdWe have                   (3A)-1=-3-242 ⟹…

Q: (b) please ?

A: Find the last three digits of 9^30 (Please use Euler's Theorem AND the Chinese Reminder Theorem)…

Q: 2x(7)+7=

A:

Q: Evaluate 2(L+W) for L= 1 and W = 4.

A: Given L=1W=4

Q: (-2) · (15 + 9) + (5 – 9 + 8)

A: Given: -2·15+9÷5-9+8

Q: 3r² – 24r + 48 =

A:

Q: (d) 1 0, 元”V元”V元 4 an =

A:

Q: 2. K 5x+5 16 35

A:

Q: nd the value of o(1999), p(101), p(243), 9(1998).

A: Phi function

Q: Find the unknown variable: C(n+1, 7) = O! Your answer

A: Value of n

Q: Find A. 0 2 (2A)-1 = BB A =

A:

Q: find the Valus of xad y for which 2.

A:

Q: N =   Q + 1     for Q              Q

A: Given: N=Q+1Q

Q: cx3 Y So So exdydx

A: .

Q: 4b2 + 8b +7 = 4

A: Given that

Q: z2+z+6=0

A:

Q: 3n+20=15

A: solve the given 3n+20=15

Q: x+9= 12 %3D

A: Given: x+9=12

Q: x2+y2=25

A:

Q: (-12)+7

A: To simplify any expression involving numbers we need to use the BODMAS rule which specifies the…

Q: t(r) dr

A:

Q: Ys+1 s7105 +?4

A:

Q: 1 - = AV25 + BV5 + C V25 + V5 + 1 A+ B + C =?

A:

Q: 2(a+3)= -12

A: Solution: Here 2(a+3) =-12

Q: (2+34)²

A:

Q: S dr 3r+5 r3-8

A:

Q: w2+7w+12=0

A: w2+7w+12=0 Solve by factoring

Q: (v-4)2

A:

Q: 2a+3a=c

A:

Q: 2r dr (1 - r)"

A:

Q: SVe -z) + 4 dz

A:

Q: P = C(1 + m) for m (business, value depreciation of equipment)

A: