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QUESTION 3 Given the following data: 1.0 1.5 2.5 3.0 4.2 5.0 5.6 91.2120 1.4432 2.2699 2.8000 4.5280 5.9669 7.2720 I i) By using linear least square method, show that the data above can be represented by y = -0.6439 + 1.31582. Start your calculation from S = n 1-0 (y - y(x₁))²

QUESTION 3 Given the following data: 1.0 1.5 2.5 3.0 4.2 5.0 5.6 91.2120 1.4432 2.2699 2.8000 4.5280 5.9669 7.2720 I i) By using linear least square method, show that the data above can be represented by y = -0.6439 + 1.31582. Start your calculation from S = n 1-0 (y - y(x₁))²

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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QUESTION 3 Given the following data: I 1.5 2.5 1.0 3.0 4.2 5.0 5.6 1.2120 1.4432 2.2699 2.8000 4.5280 5.9669 7.2720 Y 1) By be represented by y = -0.6439 + 1.31582. Start your calculation from s = Σ(u - y(π.))2 1=0 where S is the total square error. ii) The given data can be also represented by equation y = 1 + a² where a is a constant. Use the same technique in part (i), determine the value of a. iii) Given that the square error, S for linear equation in part(i) is 1.1256. Find the square error, S for part (ii). Hence determine which equation is more accurate to represent the data.
Transcribed Image Text:QUESTION 3 Given the following data: I 1.5 2.5 1.0 3.0 4.2 5.0 5.6 1.2120 1.4432 2.2699 2.8000 4.5280 5.9669 7.2720 Y 1) By be represented by y = -0.6439 + 1.31582. Start your calculation from s = Σ(u - y(π.))2 1=0 where S is the total square error. ii) The given data can be also represented by equation y = 1 + a² where a is a constant. Use the same technique in part (i), determine the value of a. iii) Given that the square error, S for linear equation in part(i) is 1.1256. Find the square error, S for part (ii). Hence determine which equation is more accurate to represent the data.
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