QUESTION 3 An arrow is shot from a height h toward a cliff. It is shot with a velocity V at an angle of 0 above the horizontal. It lands on the top edge of the cliff time t later. What is the height of the cliff? O h + t V sin© + 8 1212, where g = 9.80 m/s² O h +t V sin© - g 1212, where g = 9.80 m/s² O h + t V cose – 8 1212, where g = 9.80 m/s2 Oh + t V sine – g 1²12, where g = -9.880 m/s2
QUESTION 3 An arrow is shot from a height h toward a cliff. It is shot with a velocity V at an angle of 0 above the horizontal. It lands on the top edge of the cliff time t later. What is the height of the cliff? O h + t V sin© + 8 1212, where g = 9.80 m/s² O h +t V sin© - g 1212, where g = 9.80 m/s² O h + t V cose – 8 1212, where g = 9.80 m/s2 Oh + t V sine – g 1²12, where g = -9.880 m/s2
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![QUESTION 3
An arrow is shot from a height h toward a clif.
It is shot with a velocity Vat an angle of 8 above the horizontal.
It lands on the top edge of the cliff time t later.
What is the height of the cliff?
O h +t V sin© + g t2/2,
where g = 9.80 m/s²
O h + t V sin© – g 12/2,
where g =
9.80 m/s²
O h + t V cose - g t2/2,
where g = 9.80 m/s²
Oh + t V sine – g t212,
where g = -9.80 m/s2
QUESTION 4
01 = 26°,
02 = 37°,
%3D
T1 = 89.2 N,
g=9.80 m/s2,
m = ? kg,
Enter your answer using 3 significant figures.
T,
T,
m
w](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F20b58835-700b-4f8c-a9fe-638b3fb9ce72%2F57bf74c9-37e5-4898-8fac-93e1f7060488%2Fvloejma_processed.png&w=3840&q=75)
Transcribed Image Text:QUESTION 3
An arrow is shot from a height h toward a clif.
It is shot with a velocity Vat an angle of 8 above the horizontal.
It lands on the top edge of the cliff time t later.
What is the height of the cliff?
O h +t V sin© + g t2/2,
where g = 9.80 m/s²
O h + t V sin© – g 12/2,
where g =
9.80 m/s²
O h + t V cose - g t2/2,
where g = 9.80 m/s²
Oh + t V sine – g t212,
where g = -9.80 m/s2
QUESTION 4
01 = 26°,
02 = 37°,
%3D
T1 = 89.2 N,
g=9.80 m/s2,
m = ? kg,
Enter your answer using 3 significant figures.
T,
T,
m
w
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