- Question 25 Consider this equation 4(6x + 8) = jæ + k Find one value for j and one value for k so that there are no values of x that makes the equation true. j = 6 k = 8 A j = 24 k = 24 B j = 4 k = 32 j= 24 D k = 32

Q: Where is Yc

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Q: 1x + 2y = 4 -1x – 4y = -14

A: Given : 1x+2y = 4-1x -4y = -14

Q: Find x and y if (-3x - 9) + 4i = 6 + (3y - 2)i.

A: Given that,  (-3x - 9) + 4i = 6 + (3y - 2)i To solve for x and y, need to use below property of…

Q: Find w, where w3 = 1 + i. i? = -1.

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Q: 2x- 3x-2 6x + 3x? + 2x+1 2x- 3x-2 6x + 3x + 2x+1

A: Explanation of the answer is as follows

Q: If -y3 – 4y + a² – 5x: -y? then find at the point (3, –1). %3D

A: In this question we need to find a derivative of the given function at the point (3, -1 )

Q: Solve the following equation: =+8= -9 = 0

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Q: If y = 3 x + 1, then y 2 = _____

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Q: What is the value for this equation

A: In the graph of y = g(x), we can see that,  g(5) = 7

Q: Find the value of x in these equations i. 6x = 216 ii. 64x= 8 iii. 1000x = 0.000001 iv. 25x =…

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Q: 2a - 5y dA, R =(-5,4] x [0, 3] R.

A:

Q: I-1 I 1² +51 +8 dz

A: Given, ∫x-1x2+5x+8dx