Question 23 of 25 What is the mass in grams of 7.95 × 1015 molecules of NO?

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Question 23 of 25**

What is the mass in grams of \(7.95 \times 10^{15}\) molecules of NO?

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**Question 25 of 25**

What quantity of moles of C are formed upon complete reaction of 2 mol of B according to the generic chemical reaction:

\[ A + 2B \rightarrow C \]

**Explanation:**

This section involves two chemistry problems. 

1. **Problem about Mass of Molecules:**
   - You are asked to calculate the mass of \(7.95 \times 10^{15}\) molecules of nitrogen monoxide (NO). This will involve using Avogadro's number to convert molecules to moles and then calculating the mass using the molar mass of NO.

2. **Stoichiometry Problem:**
   - This question involves a stoichiometry calculation. Given a chemical equation \( A + 2B \rightarrow C \), you're asked to determine how many moles of product C are formed from 2 moles of reactant B. In this reaction, for every 2 moles of B reacted, 1 mole of C is formed.
Transcribed Image Text:**Question 23 of 25** What is the mass in grams of \(7.95 \times 10^{15}\) molecules of NO? --- **Question 25 of 25** What quantity of moles of C are formed upon complete reaction of 2 mol of B according to the generic chemical reaction: \[ A + 2B \rightarrow C \] **Explanation:** This section involves two chemistry problems. 1. **Problem about Mass of Molecules:** - You are asked to calculate the mass of \(7.95 \times 10^{15}\) molecules of nitrogen monoxide (NO). This will involve using Avogadro's number to convert molecules to moles and then calculating the mass using the molar mass of NO. 2. **Stoichiometry Problem:** - This question involves a stoichiometry calculation. Given a chemical equation \( A + 2B \rightarrow C \), you're asked to determine how many moles of product C are formed from 2 moles of reactant B. In this reaction, for every 2 moles of B reacted, 1 mole of C is formed.
**Question 24 of 25**

According to the balanced reaction below, calculate the quantity of moles of NH₃ gas that form when 4.20 mol of N₂H₄ liquid completely reacts:

\[ 3 \, \text{N}_2\text{H}_4(\text{l}) \rightarrow 4 \, \text{NH}_3(\text{g}) + \text{N}_2(\text{g}) \]

**Explanation:**
In this chemical equation, 3 moles of N₂H₄ produce 4 moles of NH₃. Therefore, to find out how many moles of NH₃ are produced from 4.20 moles of N₂H₄, you can use the following stoichiometry calculation:

\[ \text{(4.20 mol N₂H₄)} \times \left(\frac{4 \, \text{mol NH}_3}{3 \, \text{mol N}_2\text{H}_4}\right) = \text{moles of NH}_3 \]

Perform this calculation to get the final result for moles of NH₃ produced.
Transcribed Image Text:**Question 24 of 25** According to the balanced reaction below, calculate the quantity of moles of NH₃ gas that form when 4.20 mol of N₂H₄ liquid completely reacts: \[ 3 \, \text{N}_2\text{H}_4(\text{l}) \rightarrow 4 \, \text{NH}_3(\text{g}) + \text{N}_2(\text{g}) \] **Explanation:** In this chemical equation, 3 moles of N₂H₄ produce 4 moles of NH₃. Therefore, to find out how many moles of NH₃ are produced from 4.20 moles of N₂H₄, you can use the following stoichiometry calculation: \[ \text{(4.20 mol N₂H₄)} \times \left(\frac{4 \, \text{mol NH}_3}{3 \, \text{mol N}_2\text{H}_4}\right) = \text{moles of NH}_3 \] Perform this calculation to get the final result for moles of NH₃ produced.
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