Question 21 of 21 300.0 mL of a 0.400 M solution of Nal is diluted to 700.0 mL. What is the new concentration of the solution?

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Question 21 of 21**

A solution of 300.0 mL with a concentration of 0.400 M NaI is diluted to a final volume of 700.0 mL. What is the new concentration of the solution?

**Explanation:**

To find the new concentration after dilution, use the formula for dilution:

\[ C_1V_1 = C_2V_2 \]

Where:
- \( C_1 \) = initial concentration (0.400 M)
- \( V_1 \) = initial volume (300.0 mL)
- \( C_2 \) = final concentration (unknown)
- \( V_2 \) = final volume (700.0 mL)

Rearranging the formula to solve for \( C_2 \):

\[ C_2 = \frac{C_1V_1}{V_2} \]

Substitute the known values:

\[ C_2 = \frac{0.400 \, \text{M} \times 300.0 \, \text{mL}}{700.0 \, \text{mL}} \]

\[ C_2 = \frac{120.0}{700.0} \]

\[ C_2 = 0.171 \, \text{M} \]

The new concentration of the solution is 0.171 M.
Transcribed Image Text:**Question 21 of 21** A solution of 300.0 mL with a concentration of 0.400 M NaI is diluted to a final volume of 700.0 mL. What is the new concentration of the solution? **Explanation:** To find the new concentration after dilution, use the formula for dilution: \[ C_1V_1 = C_2V_2 \] Where: - \( C_1 \) = initial concentration (0.400 M) - \( V_1 \) = initial volume (300.0 mL) - \( C_2 \) = final concentration (unknown) - \( V_2 \) = final volume (700.0 mL) Rearranging the formula to solve for \( C_2 \): \[ C_2 = \frac{C_1V_1}{V_2} \] Substitute the known values: \[ C_2 = \frac{0.400 \, \text{M} \times 300.0 \, \text{mL}}{700.0 \, \text{mL}} \] \[ C_2 = \frac{120.0}{700.0} \] \[ C_2 = 0.171 \, \text{M} \] The new concentration of the solution is 0.171 M.
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